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Nataly_w [17]
4 years ago
11

For some reason it keeps telling me my answer is wrong please help.

Mathematics
1 answer:
harina [27]4 years ago
8 0
No worries bro your answer is correct the computer is wrong it happens
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What is 9.468 rounded to the nearest tenth
Ivan
9.47 i think thats the answer

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4 years ago
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raketka [301]

Answer:

Step-by-step explanation:

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2 years ago
afton made a chicken dish for dinner she added a 10 ounces package of vegatables and a 14 ounces package of rice to 40 ounces of
inn [45]
Often would need 30 more ounces
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3 years ago
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The chances of a tax return being audited are about 21 in 1 comma 000 if an income is less than​ $100,000 and 29 in 1 comma 000
vladimir2022 [97]

Answer:

a) p=0.021

b) p=0.029

c) Exactly one audit: P=0.0965

More than one audit: P=0.0042

Step-by-step explanation:

a) If the income is less than $100,000, there is a probability of 21 in 1,000 of being audited. This is:

p_1=\dfrac{21}{1,000}=0.021

If the income is equal or more than $100,000, there is a probability of 29 in 1,000 of being audited. This is:

p_2=\dfrac{29}{1,000}=0.029

b) If we have 5 taxpayers with incomes under $100,000, and we want to know the probability that exactly one will be audited, we can model this a binomial randome variable, with p=0.021 and n=5:

P(x=1) = \dbinom{5}{1} p^{1}q^{4}=5*0.021*0.9186=0.0965\\\\

There is a probability of 0.0965 that exactly one out of a sample of five taxpayers with incomes under $100,000 will be audited.

To calculate the probability that more than one will be audited, we use the same distribution:

P(x>1)=1-[P(x=0)+P(x=1)]\\\\\\P(x=0) = \dbinom{5}{0} p^{0}q^{5}=1*1*0.8993=0.8993\\\\\\P(x=1) = \dbinom{5}{1} p^{1}q^{4}=5*0.021*0.9186=0.0965\\\\\\P(x>1)=1-[P(x=0)+P(x=1)]\\\\P(x>1)=1-(0.8993+0.0965)\\\\P(x>1)=1-0.9958\\\\P(x>1)=0.0042

There is a probability of 0.0042 that more than one out of a sample of five taxpayers with incomes under $100,000 will be audited.

8 0
3 years ago
The manager of a company uses the function shown to model the company’s daily profit based on the price of a product in dollars,
just olya [345]

Answer: 1) The minimum price, in dollars, to avoid a loss = 22,

2) the maximum price in dollars , to avoid a loss = 53,

3) The price that results the maximum profit = 37.5 dollars

Step-by-step explanation:

Since the given function that shows the total profit,

f(x) = (x-22)(53-x)

Where x is the price of the product.

Since for avoiding the loss,

f(x) \geq 0,

⇒ (x-22)(53-x)\geq 0

If (x-22)\geq 0 \implies x\geq 22

If 53 - x \geq 0 \implies 53 \geq x

Thus, 53 ≥ x ≥ 22,

Therefore, the minimum price to avoid the loss = $ 22

And, the minimum price to avoid the loss = $ 53

f'(x) =\frac{d}{dx}[(x-22)(53-x)] = (x-22)\frac{d}{dx} (53-x)+(53-x) \frac{d}{dx}(x-22)

⇒ f'(x) = - (x-22)+(53-x) = -x+22+53-x =-2x+75

Now, For maximum or minimum,

f'(x) = 0,

⇒ -2x+75 = 0

⇒ -2x = -75

⇒ x = 37.5

f''(x) = \frac{d}{dx}(-2x+75)=-1

For x = 37.5, f''(x) is negative,

Thus, For the price of $ 37.5 dollars the company has the greatest profit.



4 0
3 years ago
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