For some reason it keeps telling me my answer is wrong please help.
1 answer:
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The values of x and y that will make LMNO a parallelogram are: x = 9, y = 1.5.
<h3>Properties of a Parallelogram</h3>- The opposite sides of a parallelogram are parallel to each other and are also of equal lengths.
- Diagonals of a parallelogram are congruent to each other and also bisect each other into equal halves.
Therefore:
ON = LM
Substitute
7x - 5 = 6x + 4
Add like terms
7x - 6x = 5 + 4
x = 9
OL = NM
Substitute
8y + 3 = x + 6
Plug in the value of x
8y + 3 = 9 + 6
8y + 3 = 15
8y = 15 - 3
8y = 12
y = 12/8
y = 1.5
Therefore, the values of x and y that will make LMNO a parallelogram are: x = 9, y = 1.5.
Learn more about parallelogram on:
Answer:
The volume of the triangular prism: 59.2
The value of the concrete used is: 16*4 = $64
Step-by-step explanation:
I think your question is missed of key information, allow me to add in and hope it will fit the original one. Please have a look at the attached photo
My answer:
As we know that, the formula to find out the volume of the triangular prism is:
V = when h is the height and a&b are the length of the two square edges. So we have:
- V =
*4*4*7.4 = 59.2
To find the concrete used in the ramp if the cost of concrete is $ 4.00 per cubic foot, we need to know the area of the ramp, which is:
S = 4*4 = 16
Hence, the value of the concrete used is: 16*4 = $64
Answer:
Correct integral, third graph
Step-by-step explanation:
Assuming that your answer was 'tan³(θ)/3 + C,' you have the right integral. We would have to solve for the integral using u-substitution. Let's start.
Given : ∫ tan²(θ)sec²(θ)dθ
Applying u-substitution : u = tan(θ),
=> ∫ u²du
Apply the power rule ' ∫ xᵃdx = x^(a+1)/a+1 ' : u^(2+1)/ 2+1
Substitute back u = tan(θ) : tan^2+1(θ)/2+1
Simplify : 1/3tan³(θ)
Hence the integral ' ∫ tan²(θ)sec²(θ)dθ ' = ' 1/3tan³(θ). ' Your solution was rewritten in a different format, but it was the same answer. Now let's move on to the graphing portion. The attachment represents F(θ). f(θ) is an upward facing parabola, so your graph will be the third one.
