Sum of n terms of a geometric series is
Sn = a1 (r^n-1)/(r-1)
a1 = 1st term = 4
r = common ratio = 12/4 = 3
so, the sum is
Sn = 4 (3^n-1)/(3-1) = 2(3^n-1)
Not very likely. Does a picture come with this question.
Answer:
Step-by-step explanation:
82 / (52+82)
82 / 134
41 / 67
