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3 years ago

9

A bookstore packs 6 books in a box. The total weight of the books 14 1/4 pounds. If each book has the same weight, what is the w

eight of one book?

2 answers:

Aleks04 [339]3 years ago

8 0

Answer:

2.375 or 2 3/8

Step-by-step explanation:

You want to do total weight over total number of items.

14 1/4 / 6 books = 2.375

Rasek [7]3 years ago

5 0

Answer:

14.25 / 6 = 2.375 or 2 3/8

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Question 1. The sticker price of a picture frame is $10 and the sales tax is 10%. What is the total price of the picture frame?

Westkost [7]

Answer:

1: $11

2: $43.19

3: $128.57

Step-by-step explanation:

10 • 1.10 = 11

39.99 • 1.08 = 43.19

43.19 • 3 = 128.57

8 0

3 years ago

Given that f(x) = x2 − 3x + 3 and g(x) = the quantity of x minus one, over four , solve for f(g(x)) when x = 5. (1 point)

Anna007 [38]

Rewrite g(x) as x-1

------

4

and then substitute this result for x in f(x) = x^2 - 3x + 3:

f(g(x)) = (x-1)^2 / 4^2 - 3(x-1)/4 + 3.

At this point we can substitute the value 5 for x:

f(g(5)) = (5-1)^2 / 4^2 - 3(5-1)/4 + 3

= 16/16 - 3(4/4) + 3 = 1 - 3 + 3 = 1

Therefore, f(g(5)) = 1.

6 0

2 years ago

If r and s are positive integers, is \small \frac{r}{s} an integer? (1) Every factor of s is also a factor of r. (2) Every prime

Yuri [45]

Answer:

<em>If statement(1) holds true, it is correct that </em> $\small \frac{r}{s}$ <em> is an integer.</em>

<em>If statement(2) holds true, it is not necessarily correct that </em> $\small \frac{r}{s}$ <em> is an integer.</em>

<em></em>

Step-by-step explanation:

Given two positive integers $r$ and $s$ .

To check whether $\small \frac{r}{s}$ is an integer:

Condition (1):

Every factor of $s$ is also a factor of $r$ .

$r \geq s$

Let us consider an example:

$s = 5^2 \cdot 2\\r = 5^3 \cdot 2^2$

$\dfrac{r}{s} = \dfrac{5^3\cdot2^2}{5^2\cdot2} = 10$

which is an integer.

Actually, in this situation $s$ is a factor of $r$ .

Condition 2:

Every prime factor of <em>s</em> is also a prime factor of <em>r</em>.

(But the powers of prime factors need not be equal as we are not given the conditions related to powers of prime factors.)

Let

$r = 2^2\cdot 5\\s =2^4\cdot 5$

$\dfrac{r}{s} = \dfrac{2^3\cdot5}{2^4\cdot5} = \dfrac{1}{2}$

which is not an integer.

So, the answer is:

<em>If statement(1) holds true, it is correct that </em> $\small \frac{r}{s}$ <em> is an integer.</em>

<em>If statement(2) holds true, it is not necessarily correct that </em> $\small \frac{r}{s}$ <em> is an integer.</em>

<em></em>

8 0

3 years ago

Suppose that a random sample of 10 adults has a mean score of 62 on a standardized personality test, with a standard deviation o

aniked [119]

Answer:

The 90% confidence interval for the mean score of all takers of this test is between 59.92 and 64.08. The lower end is 59.92, and the upper end is 64.08.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.9}{2} = 0.05$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.05 = 0.95$ , so $z = 1.645$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 1.645*\frac{4}{\sqrt{10}} = 2.08$

The lower end of the interval is the sample mean subtracted by M. So it is 62 - 2.08 = 59.92

The upper end of the interval is the sample mean added to M. So it is 62 + 2.08 = 64.08.

The 90% confidence interval for the mean score of all takers of this test is between 59.92 and 64.08. The lower end is 59.92, and the upper end is 64.08.

5 0

2 years ago

X+ 1/x =5 what is the value x²+1/x²?

irga5000 [103]

X+ 1/x= 5
⇒ (x+ 1/x)^2= 5^2
⇒ (x+ 1/x)^2= 25
⇒ x^2+ 2(x)(1/x)+ 1/x^2= 25
⇒ (x^2+ 1/x^2)+ 2*1= 25
⇒ x^2+ 1/x^2= 25 -2
⇒ x^2+ 1/x^2= 23

The final answer is 23~

3 0

3 years ago