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lilavasa [31]
3 years ago
9

A bookstore packs 6 books in a box. The total weight of the books 14 1/4 pounds. If each book has the same weight, what is the w

eight of one book?
Mathematics
2 answers:
Aleks04 [339]3 years ago
8 0

Answer:

2.375 or 2 3/8

Step-by-step explanation:

You want to do total weight over total number of items.

14 1/4 / 6 books = 2.375

Rasek [7]3 years ago
5 0

Answer:

14.25 / 6 = 2.375 or 2 3/8

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3 is 25% of what number?
stira [4]

Answer:

12

Step-by-step explanation:

25%=1/4

of=*

3=1/4x

3 divided by 1/4 or 0.25 =12

6 0
3 years ago
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Plz correct me if i'm wrong thx
OLEGan [10]

Answer:

30 fish

Step-by-step explanation:

Each fish needs 1/3 liter of water.

This means that there can be 3 fish in 1 liter of water. There are 10 liters in all. Multiply 3 with 10

3 x 10 = 30

30 fish is your answer.

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2 years ago
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ZanzabumX [31]
If it is 5ft a minute then it must be 10ft every two minutes
3 0
2 years ago
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MArishka [77]

Answer:

D = 67 inches

Step-by-step explanation:

The trend line is y = x+2  where x is the height

y = 65+2

y = 67

4 0
3 years ago
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A square napkin is folded in half on the diagonal and placed on the diameter of a round plate (see diagram below). If the folded
Crank

Answer:

A=81(\pi-1)\ in^2

Step-by-step explanation:

step 1

Find the area of the plate

The area of a circle is given by the formula

A=\pi r^{2}

we have

r=18/2=9\ in ---> the radius is half the diameter

substitute

A=\pi (9)^{2}\\A=81\pi\ in^2

step 2

Find the area of the square napkin folded (is a half of the area of the square napkin)

we know that

The diagonal of the square is the same that the diameter of the plate

Applying Pythagorean theorem

D^2=2b^2

where

b is the length side of the square

we have

D=18\ in

substitute

18^2=2b^2

solve for b^2

b^2=162\ in^2 -----> is the area of the square

Divide by 2

162/2=81\ in^2

step 3

Find the area of the space on the plate that is NOT covered by the napkin

we know that

The  area of the space on the plate that is NOT covered by the napkin, is equal to subtract the area of the square napkin folded (is a half of the area of the square napkin) from the area of the plate

so

A=(81\pi-81)\ in^2

simplify

A=81(\pi-1)\ in^2

8 0
3 years ago
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