Answer:
Coefficients are 2, 5, -1. (Coefficients are the numbers before the x)
Constant is 3 (constant is the number without any x)
2x^5+0x^4+5x^3+0x^2-x+3
You start with the biggest and end with the smallest, if anything isnt present int he original equation (for example x^4 in this case) put it in with a zero before it.
Explanation
We must the tangent line at x = 3 of the function:

The tangent line is given by:

Where:
• m is the slope of the tangent line of f(x) at x = h,
,
• k = f(h) is the value of the function at x = h.
In this case, we have h = 3.
1) First, we compute the derivative of f(x):

2) By evaluating the result of f'(x) at x = h = 3, we get:

3) The value of k is:

4) Replacing the values of m, h and k in the general equation of the tangent line, we get:

Plotting the function f(x) and the tangent line we verify that our result is correct:
Answer
The equation of the tangent line to f(x) and x = 3 is:
Answer:
-15
Step-by-step explanation:
If the soda can is a cylinder, which is most likely, than that means we need to find the height of the cone. The formula for volume of a cylinder is V= пr^2h (look at the pic for clearer formula) and we know the diameter of the soda can is 6, we know the radius is 3 because diameter is a line reaching from one point of the circle to the other. Radius is a line reaching from the center of the circle to the outside as shown in the image. We divide pi (you can put in the calculator 3.14) from 21, then we get 6.688 (if we round up) and then you must look at the formula now
it looks like
6.688=r^2h
that means we must find 3^2
that basically means 3x3 which is 9
then you have to divide that from 6.688
then you get 0.743
that is your height.
now we must find the volume of the cone. The formula for that is
V=пr^2(h/3)
now lets plug in our info
V=(3.14)(9)(0.743/3)
you get 6.999
The correct answer is the last choice.
In a compound interest equation, the first value is the initial investment. In this case, it would be 5000. After the 5000, you would enter the rate that is being used.