We are given the function:
g(x) = 6 (4)^x
Part A.
To get the average rate of change, we use the formula:
average rate of change = [g(x2) – g(x1)] / (x2 – x1)
Section A:
average rate of change = [6 (4)^1 – 6 (4)^0] / (1 – 0) =
18
Section B:
average rate of change = [6 (4)^3 – 6 (4)^2] / (3 – 2) =
288
Part B.
288 / 18 = 16
Therefore the average rate of change of Section B is 16 times
greater than in Section A.
<span>The average rate of change is greater between x = 2 to x = 3 than between
x = 1 and x = 0 because an exponential function's rate of change increases
with increasing x (not constant).</span>
Answer:

Step-by-step explanation:
Given 2 similar figures with ratio of sides = a : b, then
ratio of areas = a² : b²
Here ratio of sides = 52 : 68 = 13 : 17 ← in simplest form, thus
ratio of areas = 13² : 17² = 169 : 289 = 

will be increasing on the intervals where

and decreasing wherever

. Local extrema occur when

and the sign of

changes to either side of that point.

is positive when

is between -4 and some number between -2 and -1, and also 2 (exclusive) and 4, so you can estimate that

is increasing on the intervals [-4, -2] and (2, 4].

is negative when

is between some number between -2 and -1, up to some number less than 2. So

is decreasing on the interval [-1, 1].
You then have two possible cases for extrema occurring. The sign of

changes for some

between -2 and -1, and again to either side of

.
Answer: The sample mean is 14.98
The second one is NOT standard deviation
Step-by-step explanation: Sorry thats all i got but good luck!