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3 years ago

Help plz I'm very confused

Mathematics

1 answer:

xxMikexx [17]3 years ago

5 0

69x would be the answer

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Suppose that a department contains 7 men and 15 women. How many ways are there to form a committee with six members if it must h

Anna [14]

Answer:

7502040

Step-by-step explanation:

you can have 6 women,5 women and 1 men,4 women and 2 men,

in first case,you can place women in 15*14*13*12*11*10 ways

in second case

15*14*13*12*11*7

and in third case

15*14*13*12*7*6

and you need to sum all this numbers

3 0

2 years ago

6,2,2/3,.. Find the 8th term

Pavlova-9 [17]

Answer:

2/729

Step-by-step explanation:

This is a geometric progression.

6 0

3 years ago

Y = 2(6 + 1) + 5(3 + 2)

never [62]

Step-by-step explanation:

According to PEMDAS parentheses are first.

2(6+1) can be simplified to 12+2.

5(3+2) can be simplified to 15+10

Add these two together.

12+2+15+10

14+15+10

29+10

y=39

Note - when you have something like this in math 2(6+1) it means you need to do 2 x 6 and 2 x 1

6 0

1 year ago

Please I need help 9x + 14 ≤ 95

Wittaler [7]

ANSWER

My answer is in the photo above

7 0

2 years ago

Read 2 more answers

Given <img src="https://tex.z-dn.net/?f=%20log_%7B2%7D%28x%29%20%20%3D%20%20%5Cfrac%7B3%7D%7B%20log_%7Bxy%7D%282%29%20%7D%20

Naily [24]

Answer:

$\displaystyle y = x^{-\frac{2}{3}}$

Step-by-step explanation:

Logarithms

Some properties of logarithms will be useful to solve this problem:

1. $\log(pq)=\log p+\log q$

2. $\displaystyle \log_pq=\frac{1}{\log_qp}$

3. $\displaystyle \log p^q=q\log p$

We are given the equation:

$\displaystyle \log_{2}(x) = \frac{3}{ \log_{xy}(2) }$

Applying the second property:

$\displaystyle \log_{xy}(2)=\frac{1}{ \log_{2}(xy)}$

Substituting:

$\displaystyle \log_{2}(x) = 3\log_{2}(xy)$

Applying the first property:

$\displaystyle \log_{2}(x) = 3(\log_{2}(x)+\log_{2}(y))$

Operating:

$\displaystyle \log_{2}(x) = 3\log_{2}(x)+3\log_{2}(y)$

Rearranging:

$\displaystyle \log_{2}(x) - 3\log_{2}(x)=3\log_{2}(y)$

Simplifying:

$\displaystyle -2\log_{2}(x) =3\log_{2}(y)$

Dividing by 3:

$\displaystyle \log_{2}(y)=\frac{-2\log_{2}(x)}{3}$

Applying the third property:

$\displaystyle \log_{2}(y)=\log_{2}\left(x^{-\frac{2}{3}}\right)$

Applying inverse logs:

$\boxed{y = x^{-\frac{2}{3}}}$

7 0

2 years ago