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Nadusha1986 [10]
3 years ago
11

To classify a quadrilateral, use the slope of opposite sides to determine if the sides are ____________.

Mathematics
1 answer:
pogonyaev3 years ago
8 0
Parallel or perpendicular
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They’re equivalent because 3 • 3 is 9 and whatever you do to the top, you do to the bottom, therefore 4 • 3 is 12. That would equal 9/12.
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Which comparison is NOT true?
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HELP PLZZ will give brainliest <3
melisa1 [442]

Answer:

0

1

Step-by-step explanation:

First question:

You are given a side, a, and its opposite angle, A. You are also given side b. Use that in the law of sines and solve for the other angle, B.

\dfrac{a}{\sin A} = \dfrac{b}{\sin B}

\dfrac{10}{\sin 30^\circ} = \dfrac{40}{\sin B}

\dfrac{1}{0.5} = \dfrac{4}{\sin B}

\sin B = 2

The sine function can never equal 2, so there is no triangle in this case.

Answer: no triangle

Second question:

You are given a side, b, and its opposite angle, B. You are also given side c. Use that in the law of sines and solve for the other angle, C.

\dfrac{b}{\sin B} = \dfrac{c}{\sin C}

\dfrac{10}{\sin 63^\circ} = \dfrac{}{\sin C}

\sin C = \dfrac{8.9\sin 63^\circ}{10}

C = \sin^{-1} \dfrac{8.9\sin 63^\circ}{10}

C \approx 52.5^\circ

One triangle exists for sure. Now we see if there is a second one.

Now we look at the supplement of angle C.

m<C = 52.5°

supplement of angle C: m<C' = 180° - 52.5° = 127.5°

We add the measures of angles B and the supplement of angle C:

m<B + m<C' = 63° + 127.5° = 190.5°

Since the sum of the measures of these two angles is already more than 180°, the supplement of angle C cannot be an angle of the triangle.

Answer: one triangle

3 0
3 years ago
Ow many decimals numbers are there whose value equals the average of their digits?
kiruha [24]

Answer:

Step-by-step explanation:

there are infinite numbers between 2 and 3 having average=2.5

2.49,2.51

2.48,2.52

2.47,2.53

2.46,2.54

.................

2.491,2.509

2.492,2.508

2.493,2.507

......................

6 0
2 years ago
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