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IceJOKER [234]
3 years ago
14

Fill in the blank. A​ _____________ is used to test the hypothesis that an observed frequency distribution fits​ (or conforms​ t

o) some claimed distribution. A ▼ one-way analysis of variance goodness-of-fit test F test Student t-test is used to test the hypothesis that an observed frequency distribution fits​ (or conforms​ to) some claimed distribution.
Mathematics
1 answer:
kkurt [141]3 years ago
6 0

Answer: goodness-of-fit test

Step-by-step explanation:

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Simplify -7(-4p+1) + 2p
mariarad [96]

Step-by-step explanation:

-7(-4p+1) + 2p

-7 x -4 = 28p

-7 x 1 = -7

28p + 2p = 30p

so

30p-7

8 0
3 years ago
Experts/ace/geniuses helpp
Alex Ar [27]
Square root 144 =  12 so this is the rational number
8 0
3 years ago
What is the sum of 52 and its additive inverse?
Lisa [10]
Hello there!

The additive inverse of any number just means to flip it's value.

For example;

The number "3" would have an additive inverse of "-3".
The number "-15" would have an additive inverse of "15".

Since we have "52", we can flip the value sign of it.
We now have -52 and 52.

Since the question asked us to sum our numbers, we need to add them.

-52 + 52 = 0

The sum of 52 and its additive inverse is 0. 

 I hope this helps!
5 0
2 years ago
For a certain​ candy, 15​% of the pieces are​ yellow, 1010​% are​ red, 2020​% are​ blue, 55​% are​ green, and the rest are brown
MatroZZZ [7]
A) the probability it is brown would be 50%; the probability it is yellow or blue would be 35%; the probability it is not green is 95%; the probability it is striped is 0%.
B) the probability of all brown would be 12.5%; the probability that the third one is the first red one drawn is 8.1%; the probability that none are yellow is 61.4%; the probability that at least one is green is 14.3%.

Explanation:
A) The probability that it is brown is the percentage of brown we have.  Brown is not listed, so we subtract what we are given from 100%:
100-(15+10+20+5) = 100-(50) = 50%.  The probability that one drawn is yellow or blue would be the two percentages added together:  15+20 = 35%.  The probability that it is not green would be the percentage of green subtracted from 100:  100-5=95%.  Since there are no striped candies listed, the probability is 0%.
B) Since we have an infinite supply of candy, we will treat these as independent events.  All 3 being brown is found by taking the probability that one is brown and multiplying it 3 times:
0.5*0.5*0.5 = 0.125 = 12.5%.  
To find the probability that the first one that is red is the third one drawn, we take the probability that it is NOT red, 100-10 = 90% = 0.9, for the first two, and the probability that it IS red, 10% = 0.1, for the last:
0.9*0.9*0.1 = 0.081 = 8.1%.

The probability that none are yellow is found by raising the probability that the first one is not yellow, 100-15=85%=0.85, to the third power:

0.85^3 = 0.614 = 61.4%.

The probability that at least one is green is computed by subtracting 1-(probability of no green).  We first find the probability that all three are NOT green:
0.95^3 = 0.857375
1-0.857375 = 0.143 = 14.3%.
3 0
3 years ago
PLZ HELP ME!!!!!!!!!!!!!! 20 pOINTS
Bad White [126]

Answer:

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
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