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LenKa [72]
3 years ago
9

Which set of integers is not a pythagorean triple?

Mathematics
1 answer:
Studentka2010 [4]3 years ago
6 0
C is not a pythagorean triple
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Round 8.21 to the nearest tenth
Contact [7]

Answer: The answer would be 8.2



3 0
3 years ago
Read 2 more answers
Which of the following numbers are greater than or equal to 4/7? Is it 2/5, 0.57, or 2/3. Use explanation why.
Sergeeva-Olga [200]

Answer:

2/3

Step-by-step explanation:

2/5=0.4 and 4/7=0.571428

0.57<0.571428

---------------------------

2/3=0.6667

which is greater than or equal to 4/7

5 0
2 years ago
A bag contains 20 slips of paper Individually numbered. If a slip of paper and a letter in the word PENNSYLVANIA is chosen at ra
Soloha48 [4]

Answer:

P(M4\ n\ V) = 2.083\%

Step-by-step explanation:

Given

Paper = 20 slips

Word: PENNSYLVANIA

Required

Determine P(Multiple of 4 and V)

The sample size of the 20 slips is:

n(S) = 20

The outcomes of multiples of 4 is:

M4= \{4,8,12,16,20\}

n(M4) = 5

So, the probability of multiples of 4 is:

Pr(M4) = \frac{5}{20}

Pr(M4) = \frac{1}{4}

The sample size of PENNSYLVANIA is:

n(S) = 12

The outcome of V is:

n(V) = 1

So, the probability of V is:

P(V) = \frac{1}{12}

So, the required probability is: P(Multiple of 4 and V)

P(M4\ n\ V) = P(M4) * P(V)

P(M4\ n\ V) = \frac{1}{4} * \frac{1}{12}

P(M4\ n\ V) = \frac{1}{48}

P(M4\ n\ V) = 0.02083

Express as percentage

P(M4\ n\ V) = 0.02083 * 100\%

P(M4\ n\ V) = 2.083\%

4 0
3 years ago
The 2nd term of an exponential sequence is 9 while the 4th term is 81.find the common ratio,the first term and the sum of the fi
Thepotemich [5.8K]

Answer:

second term: 9

4th term:81

(3rd \: term)^{2}  = 9 \times 81

=729

\sqrt{729}  = 27

3rd term=27

{9}^{2}  = a1x27 \\ 81 = 27a1

a1=3 the first term

81 = 3 \times {q}^{3}

{q}^{3}  = 27

q=3

s = 3x \frac{1 -  {3}^{5} }{1 - 3}  = 364.5

5 0
3 years ago
i f N(-7,-1) is a point on the terminal side of ∅ in standard form, find the exact values of the trigonometric functions of ∅.
Natali [406]

Answer:

sin\ \varnothing = \frac{-1}{10}\sqrt 2

cos\ \varnothing = \frac{-7}{10}\sqrt 2

tan\ \varnothing = \frac{1}{7}

cot\ \varnothing = 7

sec\ \varnothing = \frac{-5}{7}\sqrt 2

csc\ \varnothing = -5\sqrt 2

Step-by-step explanation:

Given

N = (-7,-1) --- terminal side of \varnothing

Required

Determine the values of trigonometric functions of \varnothing.

For \varnothing, the trigonometry ratios are:

sin\ \varnothing = \frac{y}{r}       cos\ \varnothing = \frac{x}{r}       tan\ \varnothing = \frac{y}{x}

cot\ \varnothing = \frac{x}{y}       sec\ \varnothing = \frac{r}{x}       csc\ \varnothing = \frac{r}{y}

Where:

r^2 = x^2 + y^2

r = \sqrt{x^2 + y^2

In N = (-7,-1)

x = -7 and y = -1

So:

r = \sqrt{(-7)^2 + (-1)^2

r = \sqrt{50

r = \sqrt{25 * 2

r = \sqrt{25} * \sqrt 2

r = 5 * \sqrt 2

r = 5 \sqrt 2

<u>Solving the trigonometry functions</u>

sin\ \varnothing = \frac{y}{r}

sin\ \varnothing = \frac{-1}{5\sqrt 2}

Rationalize:

sin\ \varnothing = \frac{-1}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}

sin\ \varnothing = \frac{-\sqrt 2}{5*2}

sin\ \varnothing = \frac{-\sqrt 2}{10}

sin\ \varnothing = \frac{-1}{10}\sqrt 2

cos\ \varnothing = \frac{x}{r}

cos\ \varnothing = \frac{-7}{5\sqrt 2}

Rationalize

cos\ \varnothing = \frac{-7}{5\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}

cos\ \varnothing = \frac{-7*\sqrt 2}{5*2}

cos\ \varnothing = \frac{-7\sqrt 2}{10}

cos\ \varnothing = \frac{-7}{10}\sqrt 2

tan\ \varnothing = \frac{y}{x}

tan\ \varnothing = \frac{-1}{-7}

tan\ \varnothing = \frac{1}{7}

cot\ \varnothing = \frac{x}{y}

cot\ \varnothing = \frac{-7}{-1}

cot\ \varnothing = 7

sec\ \varnothing = \frac{r}{x}

sec\ \varnothing = \frac{5\sqrt 2}{-7}

sec\ \varnothing = \frac{-5}{7}\sqrt 2

csc\ \varnothing = \frac{r}{y}

csc\ \varnothing = \frac{5\sqrt 2}{-1}

csc\ \varnothing = -5\sqrt 2

3 0
3 years ago
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