Which set of integers is not a pythagorean triple?

Mathematics

1 answer:

Studentka2010 [4]3 years ago

6 0

C is not a pythagorean triple

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How do you write 9/10 as a decimal?

kykrilka [37]

Hey there!

In order to turn a fraction into a decimal, simply divide the numerator by the denominator. The numerator is the top part of the fraction while the denominator is the bottom part of the fraction.

So,
$\frac{9}{10}$ as a decimal would be 0.9. Simply divide 9 by 10

Answer: 0.9

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8 0

3 years ago

Read 2 more answers

PLEASE HELP

sergejj [24]

First, we find x using the given equation:
x = 4 / sin(53)
x = 5

We also know that:
Cos(∅) = base / hypotenuse
Therefore,
cos(53°) = y / 5

3 0

3 years ago

Read 2 more answers

PLEASE HELP

lisabon 2012 [21]

Step-by-step explanation:

The figure below shows a portion of the graph of the function $j\left(x\right) \ = \ 4^{x-2}$ , hence the average rate of change (slope of the blue line) between the $x$ and $x+h$ is

$\text{Average rate of change} \ = \ \displaystyle\frac{\Delta y}{\Delta x} \\ \\ \rule{3.7cm}{0cm} = \dsiplaystyle\frac{f\left(x+h\right) \ - \ f\left(x\right)}{\left(x \ + \ h \right) \ - \ x} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{f\left(x + h\right) \ - \ f\left(x\right)}{h} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{4^{x+h-2} \ - \ 4^{x-2}}{h} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{4^{x-2+h} \ - \ 4^{x-2}}{h}$

$\\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{\left(4^{x-2}\right)\left(4^{h}\right) \ - \ 4^{x-2}}{h} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{\left(4^{x-2}\right)\left(4^{h} \ - \ 1 \right)}{h}$