Answer:
(2x-3) (2x+3)
zeros, x intercepts: -3/2, 3/2
Step-by-step explanation:
4x^2 -9
We know the difference of squares is a^2 -b^2
This factors into (a-b) (a+b)
Let 4x^2 =a^2
Taking the square root
2x =a
Let b^2 =9
Taking the square root
b= 3
(4x^2-9 ) = (2x-3) (2x+3)
To find the zeros, we set the equation equal to zero
(4x^2-9 ) = (2x-3) (2x+3) =0
Using the zero product property
2x-3 =0 and 2x+3 =0
2x-3+3 = 0+3 2x+3-3 = 0-3
2x=3 2x=-3
Divide by 2
2x/2 = 3/2 2x/2 = -3/2
x = 3/2 x = -3/2
These are the zeros of the equation (which are also the x intercepts)
Answer:
1 a 2d 3a
Step-by-step explanation:
hope this help even though I'm late
Answer:A
Step-by-step explanation: Add the 1s first, you get 3, then add 3/8 and 5/8 and you Get 1. 3 +1 is 4 plus the remainder of 1/8
Answer:
substituting the given values we get,
3(1-1)+2*2
using bodmas we get
3(0)+2*2
0+2*2
0+4
4
therefore the answer is 4,thank you and mark the answer as brainliest if u find my answer helpful
Answer:
c= 1.16n
Step-by-step explanation:
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