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SVETLANKA909090 [29]

3 years ago

8

Two sides of a rectangle fence are 5 5/8 feet long. The other two sides are 6 1/4 feet long. What is the perimeter?

2 answers:

SOVA2 [1]3 years ago

3 0

11 7/8 feet is the answer bc perimeter is just adding all the side, so if 2 side = 5 5/8 and the other 2 = 6 1/4 then the sum will be 11 7/8 feet

marshall27 [118]3 years ago

3 0

Perimeter (p) = 2w+2l, l = 6 1/4 = 25/4 ft,
w = 5 5/8 = 45/8
so p = 2(45/8) + 2(25/4) = 45/4 + 25/2
= 45/4 + 50/4 = (45+50)/4 = 95/4 ft
= 23 3/4 ft

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Your body loses sodium when you sweat. Researchers sampled 38 random tennis players. The average sodium loss was 500 milligrams

Salsk061 [2.6K]

Answer:

The 99% confidence interval to estimate the mean loss in sodium in the population is between 474.10 milligrams and 525.90 milligrams. This means that we are 99% that the true mean loss in sodium in the population is between 474.10 milligrams and 525.90 milligrams.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.99}{2} = 0.005$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.005 = 0.995$ , so $z = 2.575$

Now, find M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 2.575*\frac{62}{\sqrt{38}} = 25.90$

The lower end of the interval is the mean subtracted by M. So it is 500 - 25.90 = 474.10 milligrams.

The upper end of the interval is the mean added to M. So it is 500 + 25.90 = 525.90 milligrams

The 99% confidence interval to estimate the mean loss in sodium in the population is between 474.10 milligrams and 525.90 milligrams. This means that we are 99% that the true mean loss in sodium in the population is between 474.10 milligrams and 525.90 milligrams.

7 0

3 years ago

What is the answer for this algebra 1 question -2(-6r+6)<-12+8r

maksim [4K]

You would need to distribute the parenthesis. so the equation will be 12r-12<-12+8r

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3 years ago

Triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C'.

frozen [14]

Note: Consider we need to find the vertices of the triangle A'B'C'

Given:

Triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C'.

Triangle A,B,C with vertices at A(-3, 6), B(2, 9), and C(1, 1).

To find:

The vertices of the triangle A'B'C'.

Solution:

If triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C', then

$(x,y)\to (y,-x)$

Using this rule, we get

$A(-3,6)\to A'(6,3)$

$B(2,9)\to B'(9,-2)$

$C(1,1)\to C'(1,-1)$

Therefore, the vertices of A'B'C' are A'(6,3), B'(9,-2) and C'(1,-1).

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4 years ago

What is the simplified form of this expression?

Alexxx [7]

Answer:

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Step-by-step explanation:

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Combining like terms

=> $-3x^2+4x^2+2x+5x-4+9$

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3 years ago

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