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scZoUnD [109]
3 years ago
7

What is the simplified form of this expression?

Mathematics
1 answer:
Alexxx [7]3 years ago
5 0

Answer:

Option 4

Step-by-step explanation:

=> -3x^2+2x-4 + 4x^2+5x+9

Combining like terms

=> -3x^2+4x^2+2x+5x-4+9

=> x^2+7x+5

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A car dealership has 24ft of dividers with which to enclose a rectangular play sace
alina1380 [7]

Answer:

A)  Area = A(x) = 24x - x^2

B)  Domain = {x < 24}

Step-by-step explanation:

<u>Complete Question:</u>

A car dealership has 24ft of dividers with which to enclose a rectangular play space in a corner of a customer lounge. The sides against the wall require no partition. Suppose the play space is x feet long.  

A) express the area of the play space as a function of x

B) find the domain of the function

Solution:

A)

The rectangle has area of length * width

length is x

so width will be 24 - x

Hence, the area will be:

Area = x(24 - x)

Area = A(x) = 24x - x^2

B)

Domain is the set of x values that make the function defined.

The domain will be all values less than 24.

Because if you take 24, the area would be 0 [doesn't make sense]

if you take anything over 24, the area would be negative [not possible]

Hence, the domain is:

Domain = {x < 24}

6 0
3 years ago
Fraction 13/250 as a decimal
Luba_88 [7]
To find the decimal form of 13/250 you must divide 13 by 250 which is 0.052
5 0
3 years ago
Read 2 more answers
Use this information to answer the questions. University personnel are concerned about the sleeping habits of students and the n
Oksanka [162]

Answer:

z=\frac{0.554 -0.5}{\sqrt{\frac{0.5(1-0.5)}{377}}}=2.097  

p_v =P(Z>2.097)=0.018  

If we compare the p value obtained and the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of  students reported experiencing excessive daytime sleepiness (EDS) is significantly higher than 0.5 or the half.

Step-by-step explanation:

1) Data given and notation

n=377 represent the random sample taken

X=209 represent the students reported experiencing excessive daytime sleepiness (EDS)

\hat p=\frac{209}{377}=0.554 estimated proportion of students reported experiencing excessive daytime sleepiness (EDS)

p_o=0.5 is the value that we want to test

\alpha=0.05 represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is higher than 0.5:  

Null hypothesis:p\leq 0.5  

Alternative hypothesis:p > 0.5  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.554 -0.5}{\sqrt{\frac{0.5(1-0.5)}{377}}}=2.097  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(Z>2.097)=0.018  

If we compare the p value obtained and the significance level given \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of  students reported experiencing excessive daytime sleepiness (EDS) is significantly higher than 0.5 or the half.

6 0
3 years ago
Add and simplify: 9/16 + 1/2=?
nasty-shy [4]
1 1/16 is the answer!! Hope this helps! <3 x
4 0
3 years ago
Order the following numbers from least to greatest. √11, -0.4, (-4/3), 0.8, √2
agasfer [191]

Answer:

(-4/3), 0.4, 0.8, √2, √11

Step-by-step explanation:

√11=3.316624790355399849114932736670686683927088545589353597058

0.4

(-4/3) = -1.33333333333333333333333333333333333333333333333333333333

0.8

√2=1.414213562373095048801688724209698078569671875376948073176


Thus :

(-4/3)

0.4

0.8

√2

√11

8 0
3 years ago
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