Answer:
First, find tan A and tan B.
cosA=35 --> sin2A=1−925=1625 --> cosA=±45
cosA=45 because A is in Quadrant I
tanA=sinAcosA=(45)(53)=43.
sinB=513 --> cos2B=1−25169=144169 --> sinB=±1213.
sinB=1213 because B is in Quadrant I
tanB=sinBcosB=(513)(1312)=512
Apply the trig identity:
tan(A−B)=tanA−tanB1−tanA.tanB
tanA−tanB=43−512=1112
(1−tanA.tanB)=1−2036=1636=49
tan(A−B)=(1112)(94)=3316
kamina op bolte
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Answer:
Q1: B. UHWXUQV
Q2: None of these answers equal 12 so I'll just tell you the answers for all of them in case you mistyped.
a. 66
b. 82
c. 120
d. 109
Im assuming you meant 120. If so, your answer is c.
A.)y=2/3x-7 is the answer
