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bonufazy [111]
3 years ago
8

If a town with a population of 10,000 doubles every 14 years, what will the population be in 42 years and is it modeled by a lin

ear function or an exponential function?
Mathematics
2 answers:
chubhunter [2.5K]3 years ago
8 0
Population = 10,000 x 2y 
y = periods of 14 years 

10,000 x (2 x 4) 
10,000 x 8 = 80,000

Population = 80,000 and the function is exponential  
miss Akunina [59]3 years ago
6 0

Answer:

80,000 will be the population in 42 years. It is an exponential function.

Step-by-step explanation:

If a town with a population of 10,000 doubles every 14 years.

Initial population of a town is 10,000

Point: (0,10000)

It's double every 14 years.

Point: (14,20000)

Let us suppose exponential function y=ab^x

Now using both point to find a and b

10000=a\cdot b^0\Rightarrow a=10000

Using point (14,20000) and a=10000 to solve for b

20000=10000\cdot b^{14}

2=b^{14}

b=2^{1/14}

Exponential function:

y=10000(2)^{\frac{x}{14}}

We need to find y at x=42

So, we put x=42 into function and solve for y

y=10000(2)^{\frac{42}{14}}

y=10000(2)^3

y=80,000

Thus, 80,000 will be the population in 42 years. It is an exponential function.

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State whether the triangles could be proven congruent, if possible, by SSS or SAS.
Helen [10]

Answer:

1. SSS

2. SAS

3. SAS

4. SSS

5. SAS

6. SAS

Step-by-step explanation:

1) Side FY ≅ Side CW  Given

Side FP ≅ Side CM     Given

Side YP ≅ Side MW    Given

∴ΔMCW ≅ ΔFPY by the Side-Side-Side (SSS) rule of congruency

2) ∠CBD ≅ ∠BCA given that both are alternate interior angles

Side EB ≅ Side EC and Side DB ≅ Side CA Given

ΔBED ≅ ΔAEC by Side-Angle-Side (SAS) rule of congruency

3. ∠SVU ≅ ∠SVT   Given

Side SV ≅ Side SV  by reflexive property

Side VT ≅ Side VU   Given

∴ ΔVSU ≅ ΔVST by Side-Angle-Side (SAS) rule of congruency

4. Side MN ≅ Side QP  Given

Side MQ ≅ Side NP     Given

Side NQ ≅ Side NQ    by reflexive property

∴ΔQNM ≅ ΔQNP by the Side-Side-Side (SSS) rule of congruency

5. Indirect proof

Side GL ≅ Side HL  Given

Side GJ ≅ Side HK     Given

∠JLG ≅ ∠HLK    vertically opposite angles

By sine rule

GJ/sin(∠JLG) = GL/n(∠GJL)

Similarly

HK/sin(∠HLK) = HL/n(∠HKL)

∴ ∠GJL ≅ ∠HKL

∴ ∠LGJ ≅ ∠LHK third angle of two triangles given the other two angles are congruent

∴ΔQNM ≅ ΔQNP by the Side-Angle-Side (SAS) rule of congruency

6. ∠XZY ≅ ∠XZW   Supplementary ∠s with ∠XZY = 90°

Side XZ ≅ Side XZ  by reflexive property

Side ZW ≅ Side ZY   Given

∴ ΔXYZ ≅ ΔXWZ by Side-Angle-Side (SAS) rule of congruency.

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Step-by-step explanation:

5 0
3 years ago
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Sedbober [7]

Answer: 1, 2, 5, and 10

Step-by-step explanation: To find the factors of 10, begin by dividing 10 by 1 which gives us 10. This tells us that 1 and 10 are factors of 10. Next, divide 10 by 2 which gives us 5. This tells us that 2 and 5 are also factors of 10. Next, divide 10 by 3. Notice that 10 doesn't divide evenly by 3 so 3 is not a factor of 10. Next, divide 10 by 4. Since 10 doesn't divide evenly by 4, then 4 is not a factor of 10. Next, divide 10 by 5 which gives us 2. This tells us that 5 and 2 are factors of 10 but notice that we already know that 5 and 2 are factors of 10. This means that 5 and 2 are repeat factors.

There is no need to repeat factors that we already know. In fact, as we are writing the factors of a number, it's important to understand that once we hit repeat factors, all other factors that we try will also repeat.

So here, dividing by anything greater than 5 will give us factors that we already know so we can stop here.

This means that the factors of 10 are 1, 2, 5, and 10.

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Lina20 [59]
4✔️12x

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This is the solution.
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Step-by-step explanation:

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