Factor each out:
11: 1*11
39: 3*13
35: 5*7
8: 2*2*2
since you can see no common factor just multiply them all to get 120120
Answer:
3.
Step-by-step explanation:
Find the midpoint of BC:
midpoint = (-1+5)/2, (2-2)/2 = (2, 0).
The slope of BC = (2 - -2) / (-1-5) = -2/3.
Find the equation of the right bisector of BC:
The slope = -1 / -2/3 = 3/2.
y-y1 = m(x-x1)
y - 0 = 3/2(x - 2)
y = 3/2x - 3.
Now find the equation of the median through C:
The midpoint of AB = (1 - 1)/2, (4+2)/2
= (0, 3).
The equation of the median:
The slope = (-2-3) / (5-0)
= -1.
The equation is:
y - 3 = -1(x - 0)
y -3 = -x.
Now we find the point of intersection by solving the 2 equations:
y - 3 = -x
y = 3/2x - 3
y = -x + 3
So:
3/2x - 3 = -x + 3
3/2x + x = 6
5/2 x = 6
x = 12/5.
y = -12/5 + 3
= -12/5 + 15/5
= 3/5.
The sum of the coordinates = 12/5 + 3 /5
= 15/5
= 3.
X^2 + 10 = 35 when x = -5
x + x + x = 3x = -15 when x = -5.
The answer is B because part A just restates the first equation, and Part C determines which is greater. If you want to determine the difference between the two when x = -5, part B is the best answer because it subtracts the product of one of them from the other.
Answer:
{HH, HT, TH, TT}
Step-by-step explanation:
The set of all possible outcomes in tossing a coin twice is;
{HH, HT, TH, TT}
In the first toss the coin may land Heads. In the second toss the coin may land Heads or Tails. This can be represented as;
HH, HT
Heads in the first and second tosses. Heads in the first toss followed by a Tail in the second toss.
In the first toss the coin is also likely to land Tails. In the second toss the coin may land Heads or Tails. This can be represented as;
TH, TT
Tails in the first toss followed by a Head in the second toss. Tails in the first and second tosses.
Combining these two possibilities will give us the set of all possible outcomes in tossing a coin twice is;
{HH, HT, TH, TT}
