Answer:
Step-by-step explanation:
POINTS:
- Out of every 15 students, 6 were successful in the task.
- The professors' success rate is 140% of the students' success rate.
j
v₀ = initial velocity of the freight train while it approach a road crossing = 16 km/h = 16 (5/18) m/s = 4.44 m/s
v = final velocity of the freight train after it crosses a road crossing = 65 km/h = 65 x 5/18 m/s = 18.06 m/s
t = time to do so = 10 min = 10 x 60 sec = 600 sec
acceleration is given as
a = (v - v₀ )/t
a = (18.06 - 4.44)/(600)
a = 0.023 m/s²
a = 294
2r=R
Because 2 of "r" make 1 R
First combine like terms (-9n-3n=-12n)
Then, subtract 6n on both sides (to get rid of the 6n) = -18n
Then, add 8 to both sides (does not matter) = 0
Finally divide (answer is 0)
