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2 years ago

Help help help help Number 1 and 2 in the next q

Mathematics

1 answer:

alexira [117]2 years ago

4 0

Answer:

either 81 or 162

Step-by-step explanation:

I got 81 by 27×12

162=27×12×2

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I need this<br> ctugkvhjkibnlbk;vhiglcufxoryifcuglvihk;b j;hviglucforxiy6eryfcuglvhk

Orlov [11]

Answer:

11(7 + 4) = 11 × 7 + 11 × 4

Step-by-step explanation:

11(7 + 4) = _ x 7 + 11 x _

use distributive property:

11(7 + 4) = 7 x 11 + 7 x 11

3 0

2 years ago

Read 2 more answers

Consider the fibonacci sequence below, which is the first term in the sequence to exceed 120?

gizmo_the_mogwai [7]

Answer:

144

Step-by-step explanation:

The sequence is:

0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233, 377, 610, 987, 1597, 2584, 4181, 6765, 10946

so you can see the first term larger than 120 is the 144.

3 0

2 years ago

It takes Bill 1/10 hour to walk a 1/6 mile park loop. What is Bill's unit rate, in miles per hour?

marta [7]

Answer:

.60

Step-by-step explanation:

You trying to divide them and you have to do KCF (Keep, Change, Flip) You keep the 1/10, you change the division sign into a multiplication sign, you then flip the 1/6 to 6/1. Now you multiple and you get your answer!

6 0

2 years ago

40 POINTS. When they form conical piles, granular materials such as salt, gravel, and sand settle at different "angles of repose

grandymaker [24]

Answer:

34.0 degrees, 29.6 feet in Diameter.

This is a right triangle trigonometry question.

Use half of the diameter to form the base of the triangle (19.3 ft) with a height 0f 13.

Use Inverse Tangent function to find the angle of repose

round to 34.0

then use the angle of repose to solve trigonometric function of the tangent for the radius of the other cone.

switch denominator and tangent

multiply by 2 to get diameter of second cone

14.82*2≈29.6

hopefully this helps!

7 0

2 years ago

principle is used to find the number of strings of eight uppercase English letters that start or end with the letters BO (in tha

yKpoI14uk [10]

There are 6 other positions in the string, each with 26 choices. So if you fix BO as the first two letters, there are $26^6$ possible strings that you can make.

If BO is at the end of the string, you still have $26^6$ possible strings.

Together, then, you have $2\times26^6$ possible strings.

5 0

2 years ago