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Setler [38]
3 years ago
13

A rightward force is applied to a 6-kg object to move it across a rough surface at a constant velocity. The object encounters 25

Newtons if frictional force. What would a free-body digram look like and determine the gravitational force normal force, net force, and applied (kinetic) force

Physics
1 answer:
11Alexandr11 [23.1K]3 years ago
5 0

Answer:

see the pic.

Explanation:

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The greater the frequency of the waves, the ____________ the pitch.
anzhelika [568]

Answer:

Higher.

Explanation:

The greater the frequency the bigger the amplitude gets and the greater pitch gets.

Think - more energy, bigger waves, more waves, and higher sound

7 0
3 years ago
One end of a string is fixed. An object attached to the other end moves on a horizontal plane with uniform circular motion of ra
sveticcg [70]

Answer:

If both the radius and frequency are doubled, then the tension is increased 8 times.

Explanation:

The radial acceleration (a_{r}), measured in meters per square second, experimented by the moving end of the string is determined by the following kinematic formula:

a_{r} = 4\pi^{2}\cdot f^{2}\cdot R (1)

Where:

f - Frequency, measured in hertz.

R - Radius of rotation, measured in meters.

From Second Newton's Law, the centripetal acceleration is due to the existence of tension (T), measured in newtons, through the string, then we derive the following model:

\Sigma F = T = m\cdot a_{r} (2)

Where m is the mass of the object, measured in kilograms.

By applying (1) in (2), we have the following formula:

T = 4\pi^{2}\cdot m\cdot f^{2}\cdot R (3)

From where we conclude that tension is directly proportional to the radius and the square of frequency. Then, if radius and frequency are doubled, then the ratio between tensions is:

\frac{T_{2}}{T_{1}} = \left(\frac{f_{2}}{f_{1}} \right)^{2}\cdot \left(\frac{R_{2}}{R_{1}} \right) (4)

\frac{T_{2}}{T_{1}} = 4\cdot 2

\frac{T_{2}}{T_{1}} = 8

If both the radius and frequency are doubled, then the tension is increased 8 times.

5 0
3 years ago
How does acceleration due to gravity changes wit depth?
ivann1987 [24]

Decreases

Explanation:

The acceleration due to gravity on a body decreases with depth.

Acceleration due to gravity is the change in velocity with time of a body as result of the pull of gravity or gravitational force.

  • The acceleration due to gravity tend to pull all bodies to the center of the earth.
  • As body moves away from the center of the earth, the pull becomes very more and acceleration increase.
  • But when a body approaches the center of the earth, the acceleration reduces.
  • At depth, the acceleration due to body of a body begins to decrease.

learn more:

Gravity brainly.com/question/10934170

#learn more brainly.com/question/10934170

#learnwithBrainly

7 0
3 years ago
What is potential energy??​
Murrr4er [49]

Answer:

the energy possessed by a body by virtue of its position relative to others, stresses within itself, electric charge, and other factors.

hope this helps

have a good day :)

Explanation:

3 0
3 years ago
Read 2 more answers
The gravity on mars is 3.8 m/s2 and you weigh 200 N. your mass will be??
lisabon 2012 [21]

Answer:

Mass = 52.63 kilograms

Explanation:

Given the following data;

Acceleration due to gravity = 3.8 m/s²

Weight = 200 N

To find mass;

Mathematically, the weight of a physical object is given by the formula;

Weight = mass * acceleration due to gravity

Substituting into the formula, we have;

200 = mass * 3.8

Mass = 200/3.8

Mass = 52.63 kg

3 0
3 years ago
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