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Natali5045456 [20]
3 years ago
9

hello:) I don’t really understand this graph. I thought uniform acceleration means the velocity is constant so it’s a constant g

radient?

Physics
1 answer:
Shkiper50 [21]3 years ago
5 0

Answer:

Uniform acceleration means that the object is accelerating at a constant rate. Since there is still acceleration, velocity is not constant. In fact, the velocity is increasing. This means that the object is moving faster and faster at a constant rate.

This graph is a displacement-time graph so its gradient would represent the velocity of the object. The velocity increases hence the gradient should increase (which means that the graph must be steeper and steeper with increasing time).

Constant gradient of a displacement-time graph would mean that there is no acceleration since gradient of the graph does not change so velocity is constant.

Note that it is the<em> </em><em>rate</em><em> </em><em>of</em><em> </em><em>change</em> of velocity that is constant during uniform acceleration, not velocity.

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As a freely falling object picks up downward speed. What happens to the power supplied by the gravitational force? Does it increase, decrease or stay the same? The power will increase because (Power=work/time; work=f(d); and F x d/t; FV).

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A magnitic field is used to bend a beat of electrons. What uniform magnetic field is required to bend a beam of electrons moving
jarptica [38.1K]

The strength of the magnetic field is 2.73\cdot 10^{-5} T

Explanation:

When a charged particle is moving in a uniform magnetic field, the particle experiences a force perpendicular to the direction of motion. This force is given by

F=qvB

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q is the charge of the particle

v is the velocity of the particle

B is the strength of the magnetic field

Since this force acts perpendicular to the direction of motion, the particle moves in a circular motion and the force acts as a centripetal force, so we can write:

F=qvB = m \frac{v^2}{r}

where

m is the mass of the particle

r is the radius of the circular orbit

We can re-arrange the equation in order to isolate B:

B=\frac{mv}{qr}

In this problem, we have electrons, with

m=9.11\cdot 10^{-31} kg

v=1.2\cdot 10^6 m/s

q=1.6\cdot 10^{-19} C

r = 0.25 m

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B=\frac{(9.11\cdot 10^{-31})(1.2\cdot 10^6)}{(1.6\cdot 10^{-19})(0.25)}=2.73\cdot 10^{-5} T

Learn more about magnetic fields:

brainly.com/question/3874443

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3 years ago
Why don’t we feel the gravitational force of a large object such as a skyscraper semi-truck?
Kobotan [32]

Answer:

Se the explanation below

Explanation:

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<u>Force exerted by the Earth on a human being</u>

<u />

F=G*\frac{m_{1}*m_{2}}{r^2}

Where:

G = universal gravitation constant = 6.673*10^-11 [N*m^2/kg^2]

m1 = mass of the person = 80 [kg]

m2 = mass of the earth 5.97*10^24[kg]

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<u />

Now replacing we have

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<u>Force exerted by a building on a human being</u>

<u />

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G = universal gravitation constant = 6.673*10^-11 [N*m^2/kg^2]

m1 = mass of the person = 80 [kg]

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r = distance from the building to the person = 2[m]

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