Ask question

Ask question

All categories

Ostrovityanka [42]

3 years ago

11

A^4 + 2b OVER a; if a =3 and b = 12

1 answer:

Tems11 [23]3 years ago

6 0

Answer:

105

Step-by-step explanation:

Given : a = 3, b = 12

3 ⁴ = 81

2 x 12 = 24

Result:

81 + 24

= 105

You might be interested in

Who isthe father of geometry

Yuliya22 [10]

Euclid (Euclid of Alexanderia)

7 0

3 years ago

Read 2 more answers

What is the lcd of the fractions 4/5x^2y, 8/3xy, 12/13xy^5

zheka24 [161]

195xy is ur lowest common denominator

6 0

3 years ago

Please help me. Brainliest to best answer!

Bingel [31]

Answer:

4y + 48 - 16x = 0 ~Solve for y~

4y = -48 + 16x

y = -12 + 4x

The slope is 4.

We'll use the point (1, 4) and m = 4.

Plug these into the equation: y - y1 = m(x - x1)

y - 4 = 4(x - 1)

y - 4 = 4x - 4

y = 4x

6 0

3 years ago

A line segment has the endpoints P(0, –6) and Q(–3, –7). Find the coordinates of its midpoint M.

rewona [7]

Answer:

i dont know.

Step-by-step explanation:

pls make it brainliest

5 0

2 years ago

A solution initially contains 200 bacteria. 1. Assuming the number y increases at a rate proportional to the number present, wri

GuDViN [60]

Answer:

1. $\frac{dy}{dt}=ky$

2.543.6

Step-by-step explanation:

We are given that

y(0)=200

Let y be the number of bacteria at any time

$\frac{dy}{dt}$ =Number of bacteria per unit time

$\frac{dy}{dt}\proportional y$

$\frac{dy}{dt}=ky$

Where k=Proportionality constant

2. $\frac{dy}{y}=kdt$ ,y'(0)=100

Integrating on both sides then, we get

$lny=kt+C$

We have y(0)=200

Substitute the values then , we get

$ln 200=k(0)+C$

$C=ln 200$

Substitute the value of C then we get

$ln y=kt+ln 200$

$ln y-ln200=kt$

$ln\frac{y}{200}=kt$

$\frac{y}{200}=e^{kt}$

$y=200e^{kt}$

Differentiate w.r.t

$y'=200ke^{kt}$

Substitute the given condition then, we get

$100=200ke^{0}=200 \;because \;e^0=1$

$k=\frac{100}{200}=\frac{1}{2}$

$y=200e^{\frac{t}{2}}$

Substitute t=2

Then, we get $y=200e^{\frac{2}{2}}=200e$

$y=200(2.718)=543.6=543.6$

e=2.718

Hence, the number of bacteria after 2 hours=543.6

4 0

4 years ago