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givi [52]
4 years ago
5

HELP ASAP!!!! What number should be placed in the box to help complete the division calculation?

Mathematics
1 answer:
7nadin3 [17]4 years ago
5 0
5*13= 65
65 goes in the box

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Simplify the following expression into the form a + bi, where a and b are rational numbers.
vagabundo [1.1K]
The answer is -16 - 10i.

Using the distributive property on the first part, we have:
-2i*7--2i*4i + (3+i)(-2+2i)
-14i+8i² +(3+i)(-2+2i)

Using FOIL on the last part,
-14i+8i²+(3*-2+3*2i+i*-2+i*2i)
-14i+8i²-6+6i-2i+2i²
-10i+8i²-6+2i²

Since we know that i = -1,
-10i+8(-1)-6+2(-1)
-10i-8-6-2
-16-10i
7 0
3 years ago
Read 2 more answers
Zack and his dad baked some cupcakes for his class. They put 6 cups on each of 8 plates. How many cupcakes did they put on the p
kolezko [41]

Answer:

48 cupcakes were put on the plates.

Step-by-step explanation: 6 x 8 = 48

I hoped this answer helped you solve your problem!

Sincerely, iloveyouplease123ims

8 0
3 years ago
I NEED HELP ASAP PLEASE SOLVE FOR X
Marina CMI [18]
ANSWER: x = 130°

EXPLANATION: You must add given angles and then subtract from 180°.
8 0
3 years ago
Lara has three cats: Socks, Princess, and Luna. The ratio of Sock's weight to Princess's weight is 4:5. The ratio of Princess's
romanna [79]
A = Sock's weight
b = Princess' weight
c = Luna's weight

a : b = 4 : 5
b : c = 6 : 7

at this point, we have to change the 2 ratios (a : b and b : c) into one ratio (a : b : c)
to do that, we have to change the ratio number so the number b in both ratio is the same

a : b = 4 : 5 = 24 : 30
b : c = 6 : 7 = 30 : 35
From that we can conclude that
a : b : c = 24 : 30 : 35

Since we're looking for the ratio of Sock's weight to Luna's weight, it will be
a : c = 24 : 35
6 0
3 years ago
Read 2 more answers
PLEASE HELP! A positive number is 1/3 of another number. The sum of the numbers is five less than the square of the larger numbe
antoniya [11.8K]

Answer: The numbers are 1 and 3.

Step-by-step explanation:

Let x = smaller number , y= larger number.

As per given,

x=\dfrac{y}{3}   ...(i)

x+y=y^2-5       ...(ii)

Put value of x from (i) in (ii)

\dfrac{y}{3}+y=y^2-5\\\\\Rightarrow\ \dfrac43y=y^2-5\\\\\Rightarrow\ 3y^2-4y-15=0\\\\\Rightarrow\ 3y^2-9y+5y-15=0\\\\\Rightarrow\ 3y(y-3)+5(y-3)=0\\\\\Rightarrow\ (y-3)(3y+5)=0\\\\\Rightarrow\ y=3 \ \ or\ y=\dfrac{-5}{3}

Since numbers are positive , so y=3 is correct.

And x will be 1  [from (i)]

Hence, the numbers are 1 and 3.

7 0
3 years ago
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