To compare the numbers, go from left to right examining the numbers carefully. so look at a., 3.7 can be written as 3.700, if u look, 3 and 0, it is definetly bigger than 0.01 and 0.001
Part 1
We want to find the tan of 88 degrees, 22' 45''.
88° 22' 45''
= 88 + 22/60 + 45/3600 degrees
= 88.3792°
From the calculator, obtain
tan(88.3792°) = 35.3409
Answer: 35.3409
Part 2
We want to find cot(36°).
By definition, cot(x) = 1/tan(x).
From the calculator, obtain
tan(36°) = 0.7265
Therefore
cot(36°) = 1/0.7265 = 1.3764
Answer: 1.3764
Answer: the required probability is 0.03516
Step-by-step explanation:
Given the data in the question;
let F represent dominant allele that causes fluffy fur and
f represent corresponding recessive allele that causes wiry fur
here are the possible genotypes and corresponding phenotypes;
FF = Fluffy fur
Ff = Fluffy fur
ff = Wiry fur
genotype of parents is Ff and Ff
and there cross will be; Ff x Ff
now Offspring will be;
F f
F FF Ff
f Ff ff
so the probability that the offspring will have fluffy fur = 3/4
and the probability that the offspring will have wiry fur = 1/4
The probability that the first 2 out of 4 offspring will have fluffy fur will be;
⇒ 3/4 × 3/4 × 1/4 × 1/4 = 0.03516
Therefore, the required probability is 0.03516
A i am sure i hope this helps
Answer:
all you have to do is graph them but put them in y=mx+b form first, the coordinates is the solution
