Answer:
The ball holds 113.0 cubic inches of air
Step-by-step explanation:
Firstly we need to know the shape of the ball
A ball is spherical in shape
So to know the number of cubic inches, we have to find the volume of air in the ball
Mathematically, we can do this by finding the volume of the ball using the formula for the volume of a sphere
The formula for the volume of a sphere is ;
V = 4/3 * pi * r^3
in this case, r = d/2 = 6 /2 = 3 inches
where r is the radius of the ball and d is the diameter of the ball
So, substituting these values , we have
V = 4/3 * 3.14 * 3^3 = 113.0 cubic inches
Answer:
To spend at most $93, they need to rent the room less than or equal 13 hours.
Step-by-step explanation:
<u><em>The complete question is</em></u>
To rent a certain meeting room, a college charges a reservation fee of $15 and an additional fee of $6 per hour. The chemistry club wants to spend at most $93 on renting a room. What are the possible numbers of hours the chemistry club could rent the meeting room? Use t for the number of hours. Write your answer as an inequality solved for t,
Let
t ----> the number of hours
we know that
I this problem the word "at most" means "less than or equal to"
The number of hours rented multiplied by the cost per hour, plus the reservation fee, must be less than or equal to $93
so
The inequality that represent this situation is

solve for t
subtract 15 both sides


Divide by 6 both sides

therefore
To spend at most $93, they need to rent the room less than or equal 13 hours.
Answer:
1 1/2 or 3/2
Step-by-step explanation:
8 1/4 divided by 5 1/2
Convert to improper fraction
33/4 divided by 11/2=66/44
Simplify this to get 1 1/2 or 3/2
Adjacent Angles<span> are </span>two angles<span> that share a common vertex, a common side, and no common interior points. (They share a vertex and side, but </span>do<span> not overlap.) A </span>Linear Pair<span> is </span>two<span> adjacent</span>angles<span> whose non-common sides </span>form<span> opposite rays. ... ∠1 and ∠3 are not </span>vertical angles<span> (they are a </span>linear pair<span>).</span>