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2 years ago

It is 3.67 miles to your grandparents’ home.

2 answers:

4 0

To find the amount of time, take the distance and divide by the rate. The answer will be in hours.
Notice that the distance to your drandparents' home is less than 4 miles, so it will take less than one hour.
3.67 miles / 4 miles/hour = 0.9175 hours
To change this into minutes, multiply by 60, the number of minutes in one hour:
0.9175 hours x 60 minutes/hour = 55.05 minutes, which rounds to 55 minutes.
If you are interest in numbers, you might like to read the following:
2/3 = .6666666... which rounds to .67
So 3.67 miles might actually mean 3 2/3 miles.
If it does: (3 + 2/3) / 4 x 60 = exactly 55 minutes
Jan 17, 2015 4:25:26 PM

labwork [276]2 years ago

3 0

3.67 ÷ 4
= 0.9175

Answer: 0.9175 of an hour
= 55 minutes

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Read 2 more answers

Consider the two data sets below:

alina1380 [7]

Answer:

Option c) The data sets will have the same values of their interquartile range.

Explanation:

1. The values are in order: they are in increasing oder, from lowest to highest value.

2. Calculate the interquartile range.

Interquartile range, IQR, is the third quartile, Q3, less the first quartile Q1:

IQR = Q3 - Q1

To find the first and the third quartile, first find the median:

Data Set 1: 19, 25, 35, 38, 41, 49, 50, 52, 59

[19, 25, 35, 38], 41, [49, 50, 52, 59]

↑

median = 41

Data Set 2: 19, 25, 35, 38, 41, 49, 50, 52, 99

[19, 25, 35, 38] , 41, [49, 50, 52, 99]

↑

median = 41

Now find the median of each subset: the values below the median and the values above the median.

Data set 1: First quartile

[19, 25, 35, 38],

↑

Q1 = [25 + 35] / 2 = 30

Third quartile

[49, 50, 52, 59]

↑

Q3 = [50 + 52] / 2 = 51

IQR = Q3 - Q1 = 51 - 30 = 21

Data set 2: First quartile

[19, 25, 35, 38]

↑

Q1 = [25 + 35] / 2= 30

Third quartile

[49, 50, 52, 99]

↑

Q3 = [52 + 50]/2 = 51

IQR = 51 - 30 = 21

Thus, it is shown that the data sets have will have the same values for the interquartile range: IQR = 21. (option c)

This happens because replacing one extreme value (in this case the maximum value) by other extreme value does not affect the median.

An outlier will change the range because the range is the maximum value less the minimum value.

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