Answer:
57.05
Explanation: the formula is...
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4 moles of NaOH is present in the given 160 grams of NaOH.
<h3>How we calculate moles?</h3>
Moles of any substance will be calculated as:
n = W/M, where
W = given mass of NaOH = 160 grams (given)
M = molar mass of NaOH = 40 g/mole
Moles of NaOH is calculated as:
n = 160g / 40g/mol = 4 moles
Hence, moles of sodium hydroxide (NaOH) is 4 moles.
To know more about moles, visit the below link:
brainly.com/question/24322641
Answer:
2,2,4-trimethylpentane has the higher heat of combustion in kcal/mol.
Explanation:
Heat of combustion is defined as heat evolved on combustion of 1 mole of a substance.
2,2,4-trimethylpentane has the higher heat of combustion in kcal/mol.
Heat combustion of 2,2,4-trimethylpentane = (1304 kcal/mol) and
1 mole of 2,2,4-trimethylpentane on combustion gives 8 mole sof carbon dioxide gas and 9 moles of water.
Heat combustion of ethanol = (327 kcal/mol)
1 mole of ethanol on combustion gives 2 moles of carbon dioxide gas and 3 mole of water.
Heat combustion of ethanol < Heat combustion of 2,2,4-trimethylpentane
Variable B will become lower due to variable A becoming smaller think of it like a seesaw if you put something on one side there will be a reaction on the other =)
Answer:
16.9 mmoles are needed to add to the solution
Explanation:
To solve this, we can apply the Henderson Hasselbach equation:
Acetic acid → CH₃COOH
CH₃COOH + H₂O ⇄ CH₃COO⁻ + H₃O⁺ Ka
That is the acid base equilibrium, to determine the amount:
pKa of acetic acid is 4.74
Henderson Hasselbach formula is:
pH = pKa + log (base/acid)
We replace → 4.97 = 4.74 + log (B / 10mmoles)
Let's verify mmoles of B
4.97 - 4.74 = log (B/10)
0.23 = log (B/10)
10^(0.23) = 10^(log (B/10)
1.698 = B/10
B = 1.698 . 10 → 16.9 mmoles
