D. The set of all points in a plane that are equidistant from a fixed point.
About 40%
186---100%
75-----x%
75*100 divide by 186
Answer:
,
0.00025,
,
,
,
0.025,
,

Step-by-step explanation:
We can do it this way.
First, let us clear off the powers by multipying each number by

This implies that,




















Arranging in order from the smallest, we have;
0.5,25,35,145,254,2500,12500,25000
Hence,
,
0.00025,
,
,
,
0.025,
,

Answer:
ft
Step-by-step explanation:
Given parameters:
number of inches of growth = 5inches
time duration =
month
Unknown:
Number of feet that can grow in one month = ?
Solution:
To find the rate;
Rate of growth =
Insert parameters and solve;
Rate of growth =
Rate of growth = 5inches x 
=
inches/month
Now,
Number of feet in one month:
= rate of growth x 1 month
=
inches/month x 1 month
=
inches
Since; 5inches =
feet
inches will give
ft
=
ft
Answer:
98(1 + 2√2) in² ≈ 375 in²
Step-by-step explanation:
Assuming the shaded region is outside of the square and inside of the octagon, we can find the area by subtracting the area of the square from the area of the octagon.
The area of a regular octagon is 2 (1 + √2) s². We can show this by finding the area of the square outside of the octagon, and subtracting the triangles in the corners:
(s + √2 s)² − 4 (½ (½√2 s)²)
(1 + √2)² s² − 4 (½ (s²/2))
(1 + 2√2 + 2) s² − s²
2 (1 +√2) s²
The diagonal of the inner square is equal to the width of the octagon, (1+√2) s. So the side length of the square is:
½√2 (1+√2) s
½(2+√2) s
The area of the square is therefore:
(½(2+√2) s)²
¼(2+√2)² s²
¼(4+4√2+2) s²
¼(6+4√2) s²
½(3+2√2) s²
The area of the shaded region is therefore:
2 (1 +√2) s² − ½(3+2√2) s²
½ s² (4 (1 +√2) − (3+2√2))
½ s² (4 + 4√2 − 3 − 2√2)
½ s² (1 + 2√2)
The side length of the octagon is s = 14 in, so the area is:
½ (14 in)² (1 + 2√2)
= 98(1 + 2√2) in²
≈ 375 in²