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Iteru [2.4K]
3 years ago
5

Someone please help ..

Mathematics
1 answer:
sweet [91]3 years ago
6 0
The answer is either c or d hope this helped lol
You might be interested in
if tanA= -1/7 and tanB= 3/4, where A is abtuse and B is acute, Find without using tables the value of A-B (ans/135)​
Damm [24]

Answer:

A - B =  135 \degree

Step-by-step explanation:

Recall the trigonometric identity:

\tan(A - B)=\frac{\tan A-\tan B}{1+\tan A \tan B}

We substitute;

tan A=-1/7 and tan B=3/4

\tan(A - B)=\frac{ -  \frac{1}{7} - \frac{3}{4} }{1 -  \frac{1}{7}  \times  \frac{3}{4} }

\tan(A - B) =  - 1

This implies that,

A - B =  { \tan}^{ - 1} ( - 1)

A - B =  { \tan}^{ - 1} (  1) + 90

A - B = 45+ 90

A - B =  135 \degree

5 0
3 years ago
Which expression is equivalent to One-fifth (150 x minus 80 y + 50 minus 50 x minus 25 y + 20)?
inna [77]

Answer:

The answer to your question is  20x + 21y + 14        

Step-by-step explanation:

Data

Expression             1/5 (150x - 80y + 50 - 50x - 25y + 20)

Process

1.- Multiply 1/5 by each term

                                     150/5x - 80/5y + 50/5 - 50/5x - 25/5y + 20/5

2.- Simplify

                                      30x - 16y + 10 - 10x - 5y + 4

3.- Simplify like terms

                                      (30x - 10x) + (-16y - 5y) + (10 + 4)

4.- Result

                                        20x + 21y + 14                                        

3 0
3 years ago
Read 2 more answers
8x 3x=24 what does x equal
Debora [2.8K]

8x * 3x = 24

24x = 24

x = 1

5 0
3 years ago
) Find the coordinates of the point A' which is the symmetric point
soldier1979 [14.2K]

Let, coordinate of point A' is (x,y).

Since, A' is the symmetric point  A(3, 2) with respect to the line 2x + y - 12 = 0.​

So, slope of line containing A and A' will be perpendicular to the line 2x + y - 12 = 0 and also their center lies in the line too.

Now, their center is given by :

C( \dfrac{x+3}{2}, \dfrac{y+2}{2})

Also, product of slope will be -1 .( Since, they are parallel )

\dfrac{y-2}{x-3} \times -2  = -1\\\\2y - 4 = x - 3\\\\2y - x = 1

x = 2y - 1

So, C( \dfrac{2y -1 +3}{2}, \dfrac{y+2}{2})\\\\C( \dfrac{2y + 2}{2}, \dfrac{y+2}{2})

Also, C satisfy given line :

2\times ( \dfrac{2y + 2}{2})  + \dfrac{y+2}{2} = 12\\\\4y + 4 + y + 2 = 24\\\\5y = 18\\\\y = \dfrac{18}{5}

Also,

x = 2\times \dfrac{18}{5 } - 1\\\\x = \dfrac{31}{5}

Therefore, the symmetric points isA'(\dfrac{31}{5}, \dfrac{18}{5}) .

7 0
3 years ago
Larry Thomas's charge account statement shows an unpaid balance of $800. The monthly finance charge is 1.5% of the unpaid balanc
lilavasa [31]

Answer:

The new account balance is <u>$812</u>.

Step-by-step explanation:

Given:

Larry Thomas's charge account statement shows an unpaid balance of $800.

The monthly finance charge is 1.5% of the unpaid balance.

Now, to find the new account balance.

Unpaid balance = $800.

Monthly finance charge of the unpaid balance = 1.5%.

Now, to get the new account balance:

$800 + 1.5% of $800.

=800+\frac{1.5}{100} \times 800.

=800+0.015\times 800.

=800+12.

=\$812.

Therefore, the new account balance is $812.

5 0
4 years ago
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