Answer:
Yes, because the x's do not have more than one y.
Step-by-step explanation:
x y
0 0
5 10
6 12
10 20
(That's meant to be a table). Looking at the x and y table values, you can see that none of the x's have two y's. So, this relation is a function.
I assume that the parabola in this particular problem is one whose axis of symmetry is parallel to the y axis. The formula we're going to use in this case is (x-h)2=4p(y-k). We know variables h and k from the vertex (1,20) but p is not given. However, we can solve for p by substituting values x and y in the formula with the y-intercept:
(0-1)^2=4p(16-20)
Solving for p, p=-1/16.
Going back to the formula, we can finally solve for the x-intercepts. Simply fill in variables p, h and k then set y to zero:
(x-1)^2=4(-1/16)(0-20)
(x-1)^2=5
x-1=(+-)sqrt(5)
x=(+-)sqrt(5)+1
Here, we have two values of x
x=sqrt(5)+1 and
x=-sqrt(5)+1
thus, the answers are: (sqrt(5)+1,0) and (-sqrt(5)+1,0).
Answer is acute and scalene
This triangle is acute since all angles (51, 79, 70) are all less than 90 degrees. It is a scalene triangle as well since none of the sides (10, 12.1 , 11) are equal to each other.
Here are the other definitions to help you in the future
equilateral- All sides are the same. Right - Has one right angle. Obtuse - Has an angle more than 90 degrees. Isosceles - Only two sides are the same. One is different.
Look at the picture.
Domain: -4 ≤ x ≤ 4
Range: -1 ≤ y ≤ 1
<h3>Answer: {x | -4 ≤ x ≤ 4}</h3>
A, D, E, and F are greater than -5