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wariber [46]
3 years ago
14

Two pieces of lengths 13/3 m and 3/5 m are cut off from a rope 15

Mathematics
1 answer:
garri49 [273]3 years ago
5 0

Hello there! ;) The way you solve this type of problem is you must find common denominators. So simplify 13/3= 4 1/3. So we can do 1/3*5/5=5/15. Next we must do 3/5*3/3= 9/15. So add 5/15+9/15= 14/15. And add the 4+ 14/15=          4 14/15. So then you must subtract 15 - 4 14/15= 10 1/15 I believe. I believe 10 1/15 is the remainder of the rope. You might want to check in with someone else though.

Hope I help! :D

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Plot the x-intercept(s), y-intercept, vertex, and axis of symmetry of this function:
Maslowich

Answer:

Part 1) The vertex is the point (1,-9)

Part 2) The equation of the axis of symmetry is x=1

Part 3) The y-intercept is the point (0,-8)

Part 4) The x-intercepts are (-2,0) and (4,0)

Part 5) The graph in the attached figure

Step-by-step explanation:

we have

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The vertex represent a minimum

Part 1) Find the vertex

The quadratic equation is written in vertex form

y=a(x-h)^2+k

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so

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Part 2) Find the axis of symmetry

The equation of the axis of symmetry of a vertical parabola is equal the the x-coordinate of the vertex

so

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x=1

Part 3) Find the y-intercept

we know that

The y-intercept is the value of the function when the value of x is equal to zero

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h(0)=-8

therefore

The y-intercept is the point (0,-8)

Part 4) Find the x-intercepts

we know that

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so

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(x-1)^2-9=0

solve for x

(x-1)^2=9

square root both sides

x-1=\pm3

x=1\pm3

x=1+3=4\\x=1-3=-2

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Part 5) Plot the graph of the quadratic function

Plot the following points to graph the function

vertex (1,-9)

axis of symmetry x=1

y-intercept (0,-8)

x-intercepts (-2,0) and (4,0)

The graph in the attached figure

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