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Olenka [21]
3 years ago
14

What is 6.16×106 in standard form?

Mathematics
2 answers:
zhannawk [14.2K]3 years ago
8 0
<span>6.16×10^6

10^6 = </span>10000006.16 x  1000000  = <span>6160000

</span><span>6,160,000 is your answer
</span>
hope this helps
Wewaii [24]3 years ago
5 0

Answer:

6,160,000

Step-by-step explanation:

i took the test

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Evaluate the expression.<br> 4.2°
Mariana [72]

Answer:

4.2°

Step-by-step explanation:

The result can be shown in <u>m</u><u>u</u><u>l</u><u>t</u><u>i</u><u>p</u><u>l</u><u>e</u> forms.

Exact Form: 4.2°

Decimal Form: 4.2

I hope this helps!

4 0
3 years ago
Anyone know how to do this? (10)
Hatshy [7]
MP = P - M = (0, 5) - (5, 6) = (0-5, 5-6) = (-5, -1) |MP| = √((-5)^2 + (-1)^2) = √(25+1) = √26
6 0
3 years ago
Read 2 more answers
An article in the November 1983 Consumer Reports compared various types of batteries. The average lifetimes of Duracell Alkaline
Allushta [10]

Answer:

The mean is of -0.4 hours.

Step-by-step explanation:

To solve this question, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

Mean of the sample of 64 Duracell:

By the Central Limit Theorem, 4.1 hours.

Mean of the sample of 64 Eveready:

By the Central Limit Theorem, 4.5 hours.

Mean of the difference?

Subtraction of normal variables, so we subtract the means.

4.1 - 4.5 = -0.4

The mean is of -0.4 hours.

8 0
3 years ago
A stadium has 52,000 seats. Seats sell for $42 in section A, $36 in section B, and $30 in section C. The number of seats in sect
Charra [1.4K]
Let the number of seats in section A be x, that of section B y and that of secyion C z. Then
x + y + z = 52000 . . . (1)
x = y + z . . . (2)
42x + 36y + 30z = 1960200 . . . (3)

Putting (2) into (1), gives
2x = 52000
x = 52000/2 = 26000
From (2) and (3), we have
y + z = 26000 . . . (4)
42(26000) + 36y + 30z = 1960200
36y + 30z = 1960200 - 1092000
36y + 30z = 868200 . . . (5)

(4) * 30 => 30y + 30z = 780000 . . . (6)

(5) - (6) => 6y = 88200
y = 88200/6 = 14700

From (4), z = 26000 - 14700 = 11300

Therefore, there are 26,000 seats in section A, 14,700 seats in section B and 11,300 seats in section C.
7 0
3 years ago
How do you do this math problem 5.4t+14.6-10.1t=12.8-3.5t-0.6?
lesya692 [45]
Just put the T's by adding and subtracting on one side and the numbers on the other side then divide the number with the magnitude of the final T you got
4 0
3 years ago
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