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andreyandreev [35.5K]
3 years ago
11

PLEASE ANSWER PROPERLY OR I WILL REPORT AND BLOCK YOU.

Mathematics
1 answer:
77julia77 [94]3 years ago
3 0
16² = 18² + 19² - 2(18)(19)cos(z)

256 = 324 + 361 - (684)cos(z)

256 = 685 - (684)cos(z)

-429 = -684cos(z)

cos(z) = -429/-684

z = cos⁻¹ (0.627)

z = cos⁻¹ (cos 51)    [ Cos 51 = 0.627 ]

z = 51

In short, Your Answer would be: 51

Hope this helps!
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What is the rate for $33.00 for 11 pounds of meat
riadik2000 [5.3K]

Answer:

the answer would be 3

Step-by-step explanation:

<h2>you would just have to divide 33/11. Which would give you 3</h2>
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Olivia and Hudson each have an apple. Olivia cuts hers into halves and eats one piece. Hudson cuts his into quarters and eats tw
solmaris [256]

Answer:

They ate the same amount.

Step-by-step explanation:

So Olivia has one apple. She cuts it in to 1/2 pieces. She ate 1 half of it.

Hudson cuts his into 1/4 pieces. He ate 2/4 pieces. 2/4 and 1/2 are equal so they both ate the same amount.

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X(x+1)+(x+1)(x+2)+(x+2)(x+3) solve the equation for x​
viva [34]

Answer:

3x²+9x+8

Step-by-step explanation:

x²+x+x(x+2)+1(x+2)+x(x+3)+2(x+3)

x²+x+x²+2x+x+2+x²+3x+2x+6

x²+x²+x²+x+2x+x+3x+2x+2+6

3x²+9x+8

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3 years ago
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a beverage is made by mixing 3 parts of water with 5 parts of fruit juice how many parts of water are mixed with 1 part on fruit
Fittoniya [83]

Answer:

\frac{3}{5}=0.6

Step-by-step explanation:

Given the initial ratio of 3 parts water to 5 parts fruit juice, you can set up a proportion (equivalent ratios) to determine the amount of water needed with just 1 part of fruit juice:

\frac{water}{fruit}=\frac{3}{5}=\frac{x}{1}

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divide: 5x/5 = 3/5 or x = 3/5

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Diagram 5 shows a right cylinder with a diameter of 2xcm. Given that the total surface area of the cylinder is 96cm³.Find the ma
Paraphin [41]

Given:

The diameter of the right cylinder is 2x cm.

The total surface area is 96 cm cube.

The radius is calculated as,

\begin{gathered} r=\frac{d}{2} \\ r=\frac{2x}{2} \\ r=x\text{ cm} \end{gathered}

The total surface area is,

\begin{gathered} S=2\pi rh+2\pi(r)^2 \\ 96=2\pi xh+2\pi(x^2) \\ h=\frac{96-2\pi(x^2)}{2\pi x} \end{gathered}

Volume is,

\begin{gathered} V=\pi(r)^2h \\ =\pi(x^2)\frac{96-2\pi(x^2)}{2\pi x} \\ =\frac{x(96-2\pi(x^2)}{2} \end{gathered}

Now, differentiate with respect to x,

\begin{gathered} \frac{dV}{dx}^{}=\frac{d}{dx}(\frac{x(96-2\pi(x^2)}{2}) \\ =\frac{d}{dx}\mleft(x\mleft(-\pi x^2+48\mright)\mright) \\ =\frac{d}{dx}\mleft(x\mright)\mleft(-\pi x^2+48\mright)+\frac{d}{dx}\mleft(-\pi x^2+48\mright)x \\ =1\cdot\mleft(-\pi x^2+48\mright)+\mleft(-2\pi x\mright)x \\ =84-3\pi(x^2)\ldots\ldots\ldots\ldots\text{.}(1) \end{gathered}

Now,

\begin{gathered} \frac{dV}{dx}=0 \\ 84-3\pi(x^2)=0 \\ x^2=\frac{16}{\pi} \\ x=\sqrt[]{\frac{16}{\pi}} \end{gathered}

Now, differentiate (1) with respect to x again,

\begin{gathered} \frac{d^2V}{dx^2}=\frac{d}{dx}(84-3\pi(x^2)) \\ =-6\pi x \\ At\text{ x=}\sqrt[]{\frac{16}{\pi}} \\ \frac{d^2V}{dx^2}=-6\pi\sqrt[]{\frac{16}{\pi}}

Since, the double derivative is negative.

So,\text{ the volume is maximum at }\sqrt[]{\frac{16}{\pi}}

So, the volume becomes,

\begin{gathered} V=\pi(x^2)h \\ V=\pi(\sqrt[]{\frac{16}{\pi}})^2h \\ V=\frac{16h}{\pi} \end{gathered}

Answer: maximum volume of the cylinder is,

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