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Readme [11.4K]
4 years ago
13

Can y’all please help me !!

Mathematics
1 answer:
Vilka [71]4 years ago
6 0
It’s cut off at the =
So far I got -5x-6
I hope this helps
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There are 26 cards in a box. Bryan takes 12 cards.how many cards are still in the box
Paladinen [302]
14 cards in the box left
6 0
3 years ago
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Find the lateral area and surface area of a cone with a radius of 12 and a height of 21
marishachu [46]

Answer:

The Lateral Surface Area is 911.32 square unit and

Total Surface Area is 1361.7 square unit.

Step-by-step explanation:

For a given Cone

Radius (r) = 12

Height (h) = 21

<u>For Lateral Surface Area</u>

<h3><u>Formula</u><u>:</u> </h3>

A = πr√r² + h²

A = 3.14 × 12 × √(12)² + (21)²

A = 3.14 × 12 × √144 + 441

A = 3.14 × 12 × √585

A = 37.68 × 24.18

A = 911.32 square unit

Now,

<u>For</u><u> </u><u>Total</u><u> Surface Area</u>

<h3><u>Formula:</u></h3>

A = πrl + πr²

For Slant height (l)

l² = r² + h²

l² = (12)² + (21)²

l² = 144 + 441

l² = 585

l = 24.18

So,

A = πrl + πr²

A = πr(l + r)

A = 3.14 × 12 × (24.14 + 12)

A = 3.14 × 12 × 36.14

A = 1361.7 square unit

Thus, The <u>Lateral Surface Area</u> is 911.32 square unit and <u>T</u><u>otal Surface Area</u> is 1361.7 square unit.

<u>-TheUnknownScientist</u>

6 0
3 years ago
Read 2 more answers
A members-only speaker series allows people to join for $19 and then pay $4 for every
Lera25 [3.4K]

Answer: 3

Step-by-step explanation:

Let's create a model first.

The initial fee is $19 (this is our y intercept or b)

And the pay per is $4 (this is our variable or m)

y=mx+b

y= 4x+19

To find out what the maximum number of events someone can attend for $31, we plug in different number for the x value until it's less than or equal to $31

In this case, plugging in 3 for x gives us exactly $31

y=4(3)+19= 31

6 0
3 years ago
0.04(x - 25)
kramer

Answer:

the last one is 30

Step-by-step explanation:

6 0
3 years ago
Please help me. I am so stuck.<br>​
Alexxx [7]

Answer:

Converges to -25.

Step-by-step explanation:

\sum_{k=1}^{\infty} -5 \cdot (\frac{4}{5})^{k-1} converges since r=\frac{4}{5}.

The sum is given by \frac{a_1}{1-r} where a_1 is -5.

\frac{-5}{1-\frac{4}{5}}=\frac{-5}{\frac{1}{5}}=-5(5)=-25.

6 0
3 years ago
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