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Readme [11.4K]
3 years ago
13

Can y’all please help me !!

Mathematics
1 answer:
Vilka [71]3 years ago
6 0
It’s cut off at the =
So far I got -5x-6
I hope this helps
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An airplane cruises 1 kilometer in 1/12 of a minute. what is its cruising speed?
rewona [7]

Answer:

An airplane cruises 1 kilometer in 1/12 of a minute. What is its cruising speed?<u>200</u>

5 0
3 years ago
PLEASE HELP! ILL MARK BRAINLIEST
Lunna [17]

Subtracting a number from x shifts the graph that may places tot he right

Subtracting a number at the end of the equation, shifts the graph that many units down.

The answer would be: Shift the graph of y = x^2 right 2 units and then down 10 units.

4 0
3 years ago
Read 2 more answers
X² - xy = 0<br> x + y = 1
wolverine [178]

Answer:

(0, 1 ) and (\frac{1}{2}, \frac{1}{2} )

Step-by-step explanation:

Given the 2 equations

x³ - xy = 0 → (1)

x + y = 1  → (2) ( subtract x from both sides )

y = 1 - x → (3)

Substitute y = 1 - x into (1)

x² - x(1 - x) = 0

x² - x + x² = 0

2x² - x = 0 ← factor out x from each term on the left side

x(2x - 1) = 0

Equate each factor to zero and solve for x

x = 0

2x - 1 = 0 ⇒ 2x = 1 ⇒ x = \frac{1}{2}

Substitute these values into (3) for corresponding values of y

x = 0 : y = 1 - 0 = 1 ⇒ (0, 1 )

x = \frac{1}{2} : y = 1 - \frac{1}{2} = \frac{1}{2} ⇒ ( \frac{1}{2}, \frac{1}{2} )

3 0
3 years ago
I need help with number 2 and 3 I can't get this wrong and explain !!!!
mr_godi [17]
Because on number two there is a right angle and a part of it is 66 you subtract 66 from 90 and then divide that by 31 and subtract 7. Hope that helped a little 
7 0
3 years ago
Read 2 more answers
The formula A=200e^.033t models the population of a particular city, in thousands, t years after 1998. When will the population
svetoff [14.1K]

Answer:

In the year 2010

Step-by-step explanation:

we have

A=200e^{0.033t}

where

A is the population in thousands

t is the number of years since 1998

so

For A=297 thousands

substitute and solve for t

297=200e^{0.033t}

simplify

1.485=e^{0.033t}

Apply ln both sides

ln(1.485)=ln[e^{0.033t}]

ln(1.485)=(0.033t)ln(e)

Remember that

ln(e)=1

ln(1.485)=(0.033t)

t=\frac{ln(1.485)}{0.033}

t=12\ years

1998+12=2010

7 0
3 years ago
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