Answer:
0.319 m³/s
Step-by-step explanation:
Data provided:
Initial volume in the river = 255 m³
Final volume required in the storage = 325 m³
Average outflow = 0.30 m³/s
Duration for raising the level = 1 hour = 3600 seconds
Now,
The actual volume required to raise the volume to 325 m³
= Final volume - Initial volume
= 325 m³ - 255 m³
= 70 m³
also,
the amount of outflow in 1 hour = Average rate of outflow × Time
= 0.30 m³/s × 3600 s
= 1080 m³
Therefore,
the total volume required = 1080 m³ + 70 m³ = 1150 m³
Now,
the average rate of inflow required =
=
= 0.319 m³/s