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geniusboy [140]
3 years ago
12

A weed called the boomstar vine is known for growing at a very fast rate. It can grow up to 0.5 feet per day. A. How fast in inc

hes per day can the boomstar vine grow up to? (3 points) B. How fast in inches per hour can the boomstar vine grow up to? (3 points)
Mathematics
1 answer:
Goshia [24]3 years ago
5 0
6 inches per day .25 inches per hour

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Find x and y of the triangles
Diano4ka-milaya [45]

Answer:

X = 100

Y= 140

Step-by-step explanation:

The angle of y is same with 140, x u just need to 180= 2(180-140)+x

4 0
3 years ago
The scale drawing for Lydia’s room is drawn so that 1 cm = 1 ft. If the scale drawing shows the area of her room to be 51 square
butalik [34]
Should be 51 ft. sonve 1 cm = 1 ft
3 0
3 years ago
Find the area of the rectangle. Round the answer to the nearest whole number.
Fed [463]

Answer:

The area of the given rectangle is 51

Step-by-step explanation:

First we have to find the coordinates of the vertices of the rectangle.

Then the length and breadth of it using distance formula.

The distance d between points (x₁ , y₁) and (x₂ , y₂) is given by

d= \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

Finally calculate the area of rectangle using the formula,

Area of rectangle = Length * Breadth

From the given graph, we get the coordinates of the rectangle as

A(2,4) , B(-2,3) , C(1,-9) , D(5,-8)

Breadth, AB = \sqrt{(-2-2)^{2}+(3-4)^{2}} = \sqrt{16+1} = sqrt{17}

Length, BC = \sqrt{(1+2)^{2}+(-9-3)^{2}} = \sqrt{9+144} = 3 sqrt{17}

Now, Area of rectangle = Length * Breadth = AB * BC = √17 * 3√17 = 3 *17 = 51

∴ The area of the given rectangle is 51

7 0
3 years ago
Read 2 more answers
Will someone plz help with these??<br> 18 and 19
Pavel [41]

Answer:

19 )

do cross multiply

and answer will come

Step-by-step explanation:

w+ý=z/y

8 0
3 years ago
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A rectangle is inscribed with its base on the x-axis and its upper corners on the parabola y=2−x2. What are the dimensions of su
Paul [167]

Answer:

Step-by-step explanation:

Given that a rectangle is inscribed with its base on the x-axis and its upper corners on the parabola

y=2-x^2

the parabola is open down with vertex at (0,2)

We can find that the rectangle also will be symmetrical about y axis.

Let the vertices on x axis by (p,0) and (-p,0)

Then other two vertices would be (p,2-p^2) (-p,2-p^2) because the vertices lie on the parabola and satisfy the parabola equation

Now width = 2-p^2

Area = l*w = 2(2p-p^3)

Use derivative test

I derivative = 2(2-3p^2)

II derivative = -12p

Equate I derivative to 0 and consider positive value only since we want maximum

p = \sqrt{\frac{2}{3} }

Thus width= \sqrt{\frac{2}{3} }

Length =2\sqrt{\frac{2}{3} }

Width = 2-2/3 = 4/3

3 0
3 years ago
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