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Gnom [1K]
3 years ago
6

What is the sum of 52 and its additive inverse?

Mathematics
1 answer:
Lisa [10]3 years ago
5 0
Hello there!

The additive inverse of any number just means to flip it's value.

For example;

The number "3" would have an additive inverse of "-3".
The number "-15" would have an additive inverse of "15".

Since we have "52", we can flip the value sign of it.
We now have -52 and 52.

Since the question asked us to sum our numbers, we need to add them.

-52 + 52 = 0

The sum of 52 and its additive inverse is 0. 

 I hope this helps!
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Find the two square roots of each complex number by creating and solving polynomial equations.
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Answer:

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3) w₁= 1 + 2i w₂= - 1 - 2i

4) w₁= 2- 3i w₂= -2 + 3i

5) w₁= 5 - 2i w₂= -5 + 2i

6) w₁= 5 - 3i w₂= -5 + 3i

Step-by-step explanation:

The root of a complex number is given by:

\sqrt[n]{z}=\sqrt[n]{r}(Cos(\frac{\theta+2k\pi}{n}) + i Sin(\frac{\theta+2k\pi}{n}))

where:

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θ: is the angle of the complex number to the positive axis x

n: index of the root

1) z = 15 − 8i  ⇒ r=17 θ= -0.4899 rad

w₁=\sqrt{17}(Cos(\frac{-0.4899}{2}) + i Sin(\frac{-0.4899}{2}))=4-i

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3) z = −3 + 4i  ⇒ r=5 θ= -0.9316 rad

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4) z = −5 − 12i  ⇒ r=13 θ= 0.4426 rad

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w₂=\sqrt{29}(Cos(\frac{-0.8098+2\pi}{2}) + i Sin(\frac{-0.8098+2\pi}{2}))= -5 + 2i

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w₂=\sqrt{34}(Cos(\frac{-1.0808+2\pi}{2}) + i Sin(\frac{-1.0808+2\pi}{2}))= -5 + 3i

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