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Damm [24]
3 years ago
8

A system of equations has no solution. If y=8x+7 Is One Of The Equations , Which Could Be The Other Equation?

Mathematics
2 answers:
jonny [76]3 years ago
8 0
Y=8x-7 Is the answer. I hope this helps you <3!!
Arada [10]3 years ago
3 0
A system of equations with no solutions means ur lines will be parallel and will not intersect. A parallel line will have the same slope but different y intercepts.

y = 8x + 7...slope here is 8 and y int is 7

so any equation with a slope of 8 and a y int of anything other then 7 can be ur answer.

such as :
y = 8x + 8 or y = 8x - 12, or y = 8x + 5...
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0= -115<br> sin=<br> cos =<br> tan
Alina [70]

Answer:

Step-by-step explanation:

Tito wants to buy some peanut butter to donate as much as possible.

There some brands are given with their price.

we will calculate the price of per ounce peanut butter of each brand.

A. Nutty : 12 ounces for $2.19

cost per ounce =

                        = $0.1825 ≈ $0.18 per ounce

B. Grandma's : 18 ounces for $2.79

cost per ounce =

                        = $0.155 ≈ $0.16 per ounce

C. Bee's : 0.28 ounces for $4.69

cost per ounce =

                        = $16.75 per ounce

D. Save-A-Lot : 40 ounces for $6.60

cost per ounce =

                        = $0.165 ≈ $0.17 per ounce

The lowest price is $0.16 per ounce. So he should buy Grandma's peanut butter.

8 0
3 years ago
Round 9594.20475485 to the nearest thousand
MrRissso [65]

Answer:

it is 10,000

Step-by-step explanation:

3 0
3 years ago
The plane x+y+2z=8 intersects the paraboloid z=x2+y2 in an ellipse. Find the points on this ellipse that are nearest to and fart
DiKsa [7]

Answer:

The minimum distance of   √((195-19√33)/8)  occurs at  ((-1+√33)/4; (-1+√33)/4; (17-√33)/4)  and the maximum distance of  √((195+19√33)/8)  occurs at (-(1+√33)/4; - (1+√33)/4; (17+√33)/4)

Step-by-step explanation:

Here, the two constraints are

g (x, y, z) = x + y + 2z − 8  

and  

h (x, y, z) = x ² + y² − z.

Any critical  point that we find during the Lagrange multiplier process will satisfy both of these constraints, so we  actually don’t need to find an explicit equation for the ellipse that is their intersection.

Suppose that (x, y, z) is any point that satisfies both of the constraints (and hence is on the ellipse.)

Then the distance from (x, y, z) to the origin is given by

√((x − 0)² + (y − 0)² + (z − 0)² ).

This expression (and its partial derivatives) would be cumbersome to work with, so we will find the the extrema  of the square of the distance. Thus, our objective function is

f(x, y, z) = x ² + y ² + z ²

and

∇f = (2x, 2y, 2z )

λ∇g = (λ, λ, 2λ)

µ∇h = (2µx, 2µy, −µ)

Thus the system we need to solve for (x, y, z) is

                           2x = λ + 2µx                         (1)

                           2y = λ + 2µy                       (2)

                           2z = 2λ − µ                          (3)

                           x + y + 2z = 8                      (4)

                           x ² + y ² − z = 0                     (5)

Subtracting (2) from (1) and factoring gives

                     2 (x − y) = 2µ (x − y)

so µ = 1  whenever x ≠ y. Substituting µ = 1 into (1) gives us λ = 0 and substituting µ = 1 and λ = 0  into (3) gives us  2z = −1  and thus z = − 1 /2 . Subtituting z = − 1 /2  into (4) and (5) gives us

                            x + y − 9 = 0

                         x ² + y ² +  1 /2  = 0

however, x ² + y ² +  1 /2  = 0  has no solution. Thus we must have x = y.

Since we now know x = y, (4) and (5) become

2x + 2z = 8

2x  ² − z = 0

so

z = 4 − x

z = 2x²

Combining these together gives us  2x²  = 4 − x , so

2x²  + x − 4 = 0 which has solutions

x =  (-1+√33)/4

and

x = -(1+√33)/4.

Further substitution yeilds the critical points  

((-1+√33)/4; (-1+√33)/4; (17-√33)/4)   and

(-(1+√33)/4; - (1+√33)/4; (17+√33)/4).

Substituting these into our  objective function gives us

f((-1+√33)/4; (-1+√33)/4; (17-√33)/4) = (195-19√33)/8

f(-(1+√33)/4; - (1+√33)/4; (17+√33)/4) = (195+19√33)/8

Thus minimum distance of   √((195-19√33)/8)  occurs at  ((-1+√33)/4; (-1+√33)/4; (17-√33)/4)  and the maximum distance of  √((195+19√33)/8)  occurs at (-(1+√33)/4; - (1+√33)/4; (17+√33)/4)

4 0
3 years ago
The temperature tomorrow will be above 70
attashe74 [19]

Step-by-step explanation:

False

7 0
3 years ago
Solve for x.<br> 79<br> (8x - 4)<br> 3<br> -(3x + 17)
Liono4ka [1.6K]

Answer:

-2.4

Step-by-step explanation:

maybe... i am 99.99% sure

6 0
2 years ago
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