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3 years ago

Find the solutions of the following equations.

Mathematics

1 answer:

Katyanochek1 [597]3 years ago

5 0

Answer:

a.) x = -1.5, 1.5

b.) x = 2

c.) x = 1.5

d.) x = -1, 1

e.) x = -0.943, 0.943

f.) x = -0.447, 0.447

g) x = -0.75

h.) x = -5

You can plug all these equations on Desmos

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What is the surface area of the net? *inches squared*

serious [3.7K]

9514 1404 393

Answer:

75 in^2

Step-by-step explanation:

The central vertical rectangle (including "ears") has dimensions

3 in wide by (9+2+2) = 13 in tall

Its area is

A = LW = (3 in)(13 in) = 39 in^2

The two rectangles either side of that have dimensions 2 in by 9 in. The area of each of them is

A = LW = (2 in)(9 in) = 18 in^2

The total net area is the sum of the areas of the parts:

left rectangle + central rectangle + right rectangle

= 18 in^2 + 39 in^2 + 18 in^2 = 75 in^2 . . . . surface area of the net

3 0

2 years ago

Pleaseeee helpppppppppp

o-na [289]

Answer:

25 ft^2

Step-by-step explanation:

In direct variation, if y varies directly with x, then the equation has the form

y = kx,

where k is the constant of proportionality. y is proportional to x.

Let's call the area y and the distance x.

Here, the area varies with the square of the distance, so the equation has the form

y = kx^2

Here, y is proportional to the square of x.

We can find the value of k by using the given information.

y = kx^2

When x = 20 ft, y = 16 ft^2.

16 = k(20^2)

k = 16/400

k = 1/25

The equation of the relation is:

y = (1/25)x^2

Now we use the equation we found to answer the question.

What is y (the area) when x (the distance) is 25 ft?

y = (1/25)x^2

y = (1/25)(25^2)

y = 25

Answer: 25 ft^2

5 0

2 years ago

3/8 + 4/8 = ? please help

maksim [4K]

The answer is going to be 7/8. hope that helped

4 0

3 years ago

Read 2 more answers

1 point

kolezko [41]

Answer:

Step-by-step explanation:

I pretty sure that its 6 if nt sorry

7 0

3 years ago

AveGali [126]

Answer:

Total time taken by walking, running and cycling = 22 minutes.

Step-by-step explanation:

Let the speed of walking = x

As given,

The distance of walking = 1

Now,

As $Time = \frac{Distance }{Speed}$

⇒ Time traveled by walking = $\frac{1}{x}$

Now,

Given that - He runs twice as fast as he walks

⇒Speed of running = 2x

Also given distance traveled by running = 1

Time traveled by running = $\frac{1}{2x}$

Now,

Given that - he cycles one and a half times as fast as he runs.

⇒Speed of cycling = $\frac{3}{2}$ (2x) = 3x

Also given distance traveled by cycling = 1

Time traveled by cycling = $\frac{1}{3x}$

Now,

Total time traveled = Time traveled by walking + running + cycling

= $\frac{1}{x}$ + $\frac{1}{2x}$ + $\frac{1}{3x}$

= $\frac{6+3+2}{6x} = \frac{11}{6x}$

If he cycled the three mile , then total time taken = $\frac{1}{3x}$ + $\frac{1}{3x}$ + $\frac{1}{3x}$ = x

Given,

He takes ten minutes longer than he would do if he cycled the three miles

⇒x + 10 = $\frac{11}{6} x$

⇒ $x - \frac{11}{6} x = -10$

⇒ $-\frac{5}{6}x = -10$

⇒x = $\frac{60}{5}$ = 12

⇒x = 12

∴ we get

Total time traveled by walking + running + cycling = $\frac{11}{6} x = \frac{11}{6} (12) = 11 (2) = 22$ min

7 0

2 years ago