Finding the area of A=1/2bh
1 answer:
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#4) From the reference angle of 58° we can see that we have the side opposite to that angle as well as the hypotenuse. Recall that sin=opp/hyp so we are going to use sine to find that side
sin(58°) =
(multiply both sides by 19 to isolate x)
19 sin(58°) = x (plug into calculator)
16.1 = x
#5) From the reference angle of 56°, we see that we have the adjacent and the opposite sides. Remember that tan=opp/adj so we will use tangent to find x
tan(56°) =
(multiply both sides by 
)
(flip them so x is on the top)
[tex] \frac{12}{tan(56)} = x
8.1 = x
sin(58°) =
19 sin(58°) = x (plug into calculator)
16.1 = x
#5) From the reference angle of 56°, we see that we have the adjacent and the opposite sides. Remember that tan=opp/adj so we will use tangent to find x
tan(56°) =
[tex] \frac{12}{tan(56)} = x
8.1 = x