Answer:
The second choices is the answer
{(-6,6), (8, 2), (8, -1), (3,3)} as you can see there's a repeating value of x or the Domain which is the 8.
Hello,
f(g(x))=f(2x+2)=4(2x+2)+21=8x+29
f(g(7))=8*7+29=56+29=85
Answer:
m∠Y=50°
Step-by-step explanation:
So, we know that ∠S+∠Y=90 and that m∠S=2(m∠Y)-60.
If you plug those things into the equation, you get (2[m∠Y]-60)+m∠Y=90.
Then you multiply 2 and m∠Y: 2m∠Y-60+m∠Y=90.
Combine like terms: 3m∠Y-60=90.
Then you add 60 to both sides: 3m∠Y=150
Divide 3 on both sides: 3∠Y=50
The question is:
Check whether the function:
y = [cos(2x)]/x
is a solution of
xy' + y = -2sin(2x)
with the initial condition y(π/4) = 0
Answer:
To check if the function y = [cos(2x)]/x is a solution of the differential equation xy' + y = -2sin(2x), we need to substitute the value of y and the value of the derivative of y on the left hand side of the differential equation and see if we obtain the right hand side of the equation.
Let us do that.
y = [cos(2x)]/x
y' = (-1/x²) [cos(2x)] - (2/x) [sin(2x)]
Now,
xy' + y = x{(-1/x²) [cos(2x)] - (2/x) [sin(2x)]} + ([cos(2x)]/x
= (-1/x)cos(2x) - 2sin(2x) + (1/x)cos(2x)
= -2sin(2x)
Which is the right hand side of the differential equation.
Hence, y is a solution to the differential equation.
Answer:
i
Step-by-step explanation:
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