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elena55 [62]
3 years ago
11

Ten friends share 6 pizza what fraction does each friend get

Mathematics
2 answers:
riadik2000 [5.3K]3 years ago
8 0
1.6 pieces of pizza for each person.
QveST [7]3 years ago
6 0
6p/10f=3p/5f=0.6p/f

Each friend gets 6/10 of a pizza.  (or 4.8 slices :D)
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classify the pair of angles. (supplementary, adjacent, vertical, or complementary) then find the value of x.
earnstyle [38]

Answer:

Supplementary angles; 148°

Step-by-step explanation:

180° - 32° = 148° (supplementary angles)

8 0
2 years ago
Find the slope of the line that passes through<br> (10, 1) and (6,2)
Daniel [21]

Answer:

m=-1/4

Step-by-step explanation:

2-1/6-10=1/-4

-1/4 is the slope

7 0
2 years ago
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WHAT IS THE ANSWER ?? PLEASE HELP !!
Jlenok [28]

Answer:

B. 43°

Step-by-step explanation:

Internal angles of the triangle are:

  • 180°-90°=90° and
  • 180°-133°= 47°

So It is a right triangle and the missing angle is:

  • p= 90°- 47°= 43°
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2 years ago
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1.95 is 1.5% of what number?
stiks02 [169]

Hello there, to answer your question...

<h2>1.95 is 1.5% of 130.</h2><h2 />

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4 0
3 years ago
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A machine that produces ball bearings has initially been set so that the true average diameter of the bearings it produces is .5
Elodia [21]

Answer:

7.3% percentage of the bearings produced will not be acceptable.

Step-by-step explanation:

Consider the provided information.

Average diameter of the bearings it produces is .500 inches. A bearing is acceptable if its diameter is within .004 inches of this target value.

Let X is the normal random variable which represents the diameter of bearing.

Thus, 0.500-0.004<X<0.500+0.004

0.496<X<0.504

The bearings have normally distributed diameters with mean value .499 inches and standard deviation .002 inches.

Use the Z score formula: \frac{X-\mu}{\sigma}

Therefore

\frac{0.496-0.499}{0.002}\leq z\leq \frac{0.504-0.499}{0.002}

\frac{-0.003}{0.002}\leq z\leq \frac{0.005}{0.002}

-1.5\leq z\leq 2.5

Now use the standard normal table and determine the probability of that a ball bearing will be acceptable.

P(-1.5\leq z\leq 2.5)=0.9938-0.0668=0.9270

We need to find the percentage of the bearings produced will not be acceptable.

So subtract it from 1 as shown.

1-0.9270=0.073

Hence, 7.3% percentage of the bearings produced will not be acceptable.

3 0
3 years ago
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