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mr Goodwill [35]
4 years ago
13

Solve the equation for the red variable(C)in R-C=P

Mathematics
1 answer:
BARSIC [14]4 years ago
5 0

If you want to solve the equation

R-C=P

for C, you can work like this: subtract P from both sides:

R-C-P = 0

Add C to both sides:

R-P=C

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NEED THIS ANSWERED ASAP!
Karo-lina-s [1.5K]
<h2>PART A</h2><h3>5-Number-Summary:</h3>

Town A: 3, 4.5, 6, 9, 20

--------------------------

Minimum: 3

Quartile Q1: 4.5

Median: 6

Quartile Q3: 9

Maximum: 20

Town B:  3, 4, 6, 8.5, 9

---------------------------

Minimum: 3

Quartile Q1: 4

Median: 6

Quartile Q3: 8.5

Maximum: 9

---------------------------------------------------------------

<h3>Interquartile Range:</h3>

(Median of each set)

6 <em>(town A)</em> - 6 <em>(town B)</em> = 0

<h2>PART B:</h2>

Are they symmetric?

<em>No, I believe not,</em> they don't align center in the same way, according to the pictures I've attached. The one with a short box is Town A, the bigger box is Town B.

5 0
3 years ago
The gcd of two numbers is 7 and their lcm is 140. If one of the numbers is 20 find the other number ​
sweet [91]

Answer:

49

Step-by-step explanation:

Product of GCD and LCM = Product of the 2 numbers

Product of GCD and LCM = 7 × 140 = 980

One number is 20 so let the other number be N

20×N=7×140

20N=980

2N=98

N=49

so the other number is 49

6 0
4 years ago
Read 2 more answers
Which model represents (-6)-(-3) on a number line
slega [8]

Answer: Start at six and go right three times

Step-by-step explanation:

6 0
3 years ago
What is the math formula for
dybincka [34]

Answer:

somewhere between 15,000-15,900

8 0
4 years ago
Someone please help I’m so confused
Veronika [31]

Answer:

80 - 12 - 5f

Step-by-step explanation:

You have a total of eighty seeds in all.

Minus the twelve seeds Demi planted.

The number of friends she gave seeds to is unclear.

To find out how many seeds she gave you'd have to

multiply five by the number of friends.

It's is all being subtracted from the total.

Hope this helps. ;)

5 0
3 years ago
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