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mr Goodwill [35]
3 years ago
13

Solve the equation for the red variable(C)in R-C=P

Mathematics
1 answer:
BARSIC [14]3 years ago
5 0

If you want to solve the equation

R-C=P

for C, you can work like this: subtract P from both sides:

R-C-P = 0

Add C to both sides:

R-P=C

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Write √3 x √6 in the form b√2 where b is an integer
bagirrra123 [75]

Answer:

3√2

Step-by-step explanation:

√3 x √6

= √3×6

= √18

= √9×2

= √9 × √2

= 3 × √2

= 3√2

I hope this was helpful, please rate as brainliest  

7 0
3 years ago
ALGEBRA 2!!!!!!!HELP
Inessa [10]

Answer:

x = - 1, x = - 11

Step-by-step explanation:

Given

2| x + 6 | - 4 = 6 ( add 4 to both sides )

2|x + 6 | = 10 ( divide both sides by 2 )

| x + 6 | = 5

The absolute value function always gives a positive result, but the expression inside can be positive or negative, that is

x + 6 = 5 or - (x + 6) = 5

solve both

x + 6 = 5 ( subtract 6 from both sides )

x = - 1

or

- (x + 6) = 5 , that is

- x - 6 = 5 ( add 6 to both sides )

- x = 11 ( multiply both sides by - 1 )

x = - 11

8 0
3 years ago
On a linear X temperature scale, water freezes at −115.0°X and boils at 325.0°X. On a linear Y temperature scale, water freezes
belka [17]

Answer:

The current temperature on the X scale is 1150 °X.

Step-by-step explanation:

Let is determine first the ratio of change in X linear temperature scale to change in Y linear temperature scale:

r = \frac{\Delta T_{X}}{\Delta T_{Y}}

r = \frac{325\,^{\circ}X-(-115\,^{\circ}X)}{-25\,^{\circ}Y - (-65.00\,^{\circ}Y)}

r = 11\,\frac{^{\circ}X}{^{\circ}Y}

The difference between current temperature in Y linear scale with respect to freezing point is:

\Delta T_{Y} = 50\,^{\circ}Y - (-65\,^{\circ}Y)

\Delta T_{Y} = 115\,^{\circ}Y

The change in X linear scale is:

\Delta T_{X} = r\cdot \Delta T_{Y}

\Delta T_{X} = \left(11\,\frac{^{\circ}X}{^{\circ}Y} \right)\cdot (115\,^{\circ}Y)

\Delta T_{X} = 1265\,^{\circ}X

Lastly, the current temperature on the X scale is:

T_{X} = -115\,^{\circ}X + 1265\,^{\circ}X

T_{X} = 1150\,^{\circ}X

The current temperature on the X scale is 1150 °X.

5 0
3 years ago
A polynomial is to be constructed that will touch the x axis at most 8 times. What is the minimum degree of the polynomial?
Harman [31]
The maximum number of roots to a polynomial of order n is n roots. Take the example of a quadratic (order 2) which can intersect the x-axis a maximum of 2 times, and similarly a cubic (order 3) 3 times maximum.

Hence for 8 intersections, minimum order = 8
7 0
3 years ago
Please help me with this will give BRAINLIST to best answer
In-s [12.5K]

Answer:

\frac{3}{b^{0}b^{4}  }

Step-by-step explanation:

Move b^{-4} to the denominator in \frac{3b^{-4} }{b^{0} }

using the negative exponent rule b^{-n} =\frac{1}{b^{n} }

3 0
3 years ago
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