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zhannawk [14.2K]
3 years ago
9

Tell me 9 numbers that round to 50

Mathematics
2 answers:
tangare [24]3 years ago
7 0
45, 46, 47, 48, 49, 51, 52, 53, 54
jolli1 [7]3 years ago
3 0
46 47 48 49 50 51 52 53 54
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Mark earns $12.25 an hour. How much did he make last week if he worked 25 hours?
serious [3.7K]

Answer:

306.25

Step-by-step explanation:

12.25(25)

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3 years ago
What is the SURFACE AREA of this 3-D figure?"
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Is 5m

Step-by-step explanation:

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3 years ago
Explain plz so I can understand.
olchik [2.2K]
Okay so you are going to really just add 30 + 9 here and that means you have 30 tens and 9 ones or a 30 in the tens place and a 9 in the ones place.

I hope i broke that down well enough.

I hope this helped :)
7 0
4 years ago
Point A is at (2,-8) and the point C is at (-4,7). Find the coordinates of point B on AC such that the ratio of AB to BC is 2:1.
pentagon [3]

Answer:

The coordinates of point B are (-2, 2)

Step-by-step explanation:

We have two points: A and C.

The coordinates for A are (2, -8) and the coordinates for C are (-4, 7).

We have to find the coordinates of the point B, that satisfies the condition that the distance AB is 2 times the distance BC.

We also know that B is a point of the line AC.

We can calculate the line AC as a linear function y=mx+b.

The slope m is:

m=\dfrac{y_c-y_a}{x_c-x_a}=\dfrac{7-(-8)}{-4-2}=\dfrac{15}{-6}=-2.5

Then, the y-intercept b can be calculated using the coordinates of one of the points, in this case point A:

y=-2.5x+b\\\\b=y_a+2.5x_a=-8+2.5*2=-8+5=-3

Then, we know that B is a point of the linear function y=-2.5x-3, within the range x ∈ (-4; 2).

To have a ratio AB to BC of 2 to 1, we can divide the length of the line AC in 3 parts, and the point B will be located in the  end of the segment nearer to point C.

In the picture attached, you can see the division of the segment AC in three parts and the location of point B=(x, y).

Applying the Thales theorem, we can divide the segment in the y-axis in three and calculate y, and the same for the x-axis.

Then, the coordinate y for the point B is:

y=y_c-(y_c-y_a)/3\\\\y=7-[7-(-8)]/3=7-15/3=7-5=2\\\\\\x=x_c-(x_c-x_a)/3\\\\x=-4-(-4-2)/3=-4-(-6)/3=-4+2=-2

Then, the point B has coordinates (-2, 2).

We can verify the distances as:

AB=\sqrt{(2-(-2))^2+((-8)-2)^2}=\sqrt{16+100}=\sqrt{116}\\\\\\BC=\sqrt{((-2)-(-4))^2+(2-7)^2}=\sqrt{4+25}=\sqrt{29}\\\\\\\dfrac{AB}{BC}=\dfrac{\sqrt{116}}{\sqrt{29}}=\sqrt{\dfrac{116}{29}}=\sqrt{4}=2

4 0
3 years ago
What is the distance between (5,7) and (11,-1)
ra1l [238]

Answer:

10 units

Step-by-step explanation:

To find the distance between two points on a graph, we use the distance formula d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2 where d is the distance between points (x_1,y_1) and (x_2,y_2).

For this problem, we will identify (x_1,y_1)\rightarrow(5,7) and (x_2,y_2)\rightarrow(11,-1):

d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}\\\\d=\sqrt{(-1-7)^2+(11-5)^2}\\\\d=\sqrt{(-8)^2+(6)^2}\\\\d=\sqrt{64+36}\\\\d=\sqrt{100}\\\\d=10

Therefore, the distance between (5,7) and (11,-1) is 10 units

6 0
2 years ago
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