Select the three models that represent 35%.

In the equation x/35 = 7, what is the value of x? a. 7 b. 245 c. 35 d. 5

Marianna [84]

So we wan't to get the value of x in the equation x/35=7. To get x we need to multiply both sides of the equation with 35 and then we get: x=7*35. So after multiplying we get x= 245. To check the solution lets divide 245/7=35. So the correct answer is b. 245.

6 0

3 years ago

Read 2 more answers

Write the first four terms of a sequence given the recursive rule below: f (n) = f(n-1) -4, for all n > 2 and f(1) =32

Mars2501 [29]

I don’t know I just want points bye hdhdjjdjddjdjdjjjfjtfjgktk

7 0

3 years ago

Help with these precalculus problems, please.

likoan [24]

Yay, easy peasy, nice refresher

53. evaluate for x=infinity
we get 100/(infiniy^2-5) which is basically 100/infinity which is a very small number so about 0

54.
vertical assemtotes, neato
that is where the denomenator equals 0
but wait, simplify first
ok, fraction is simplified (anything factored out would be a hole)
so set the denom to 0 and solve
x^2-5=0
(x-√5)(x+√5)=0
x=-√5 and √5
vertical assemtotes at x=-√5 and x=√5

55. horizontal assemtotes
for the function p(x)/f(x)

if p(x) has lower degree than f(x) then y=0 is the horizontal assemtote

if p(x) has equal degree to f(x) then divide the leading coefients of p(x) and f(x)

if p(x) has greater degree than f(x) then we got slant assemtotes

100/(x^2-5)
100 has lower degree than x^2
y=0 is the horizontal assemtote

56. evalate for x=-5
we get -150/-10=150/10=15
the limit is 15

57. that negative on the right side means that we must approach it from the left
let's see if we can factor out the denomenator
nope
so go and evaluate values like 4, 4.5, 4.9, etc, approaching x=5 from the left
we keep getting smaller and smaller valuse
this make sense because as x approaches 5, we get 30(c)/(c-5) where c is close to 5, and as c appraoches 5 very close, the top part is appraoching 150 but the bottom approaches a very small negative number, and if we do something like 150/-0.00000000001, we get a very negative number
the limit is negative infinity

alternately, you could figure that there is a vertical assemtote at x=5 so we can see that if we aproximaate closer and closer values, we get smaller values. so from what we know about assemtotes, expecially vertical ones, we say that it approaches negative infinity

58.
evalauating we get infintity/inifinty, not helpful
hmmm, is there a horizontal assemtote to help us?
the degree of top is higher so we got a slant assemtote
the only way is to use long division to divide the top by the bottom (see attachment)
we get
$\frac{1}{2}x-\frac{1}{4}+\frac{\frac{1}{4}}{2x+1}$
the slant assemtote is $y=\frac{1}{2}x-\frac{1}{4}$
as you can see, as x approaches infinity, y also will approach infinity

ANSWERS:
53. 0
54. VA is x=-√5 and x=√5
55. HA is y=0
56. the limit is 15
57. the limit is -∞
58. the limit is ∞

6 0

3 years ago

Ben, Bob and Bill are triplets. They were born 5 years before their sister, Stephanie. This year the product of their four ages

maria [59]

Let the triplets' age be x, the sister's age is then x-5.
product of their age as given
xÂł.(x-5)=75749+x+x+x+x-5
x^4 - 5xÂł= 4x +75744
x^4 - 5xÂł -4x -75744=0
resolving the equation,
we get
x = 18
therefore, Age of ben,bob and bill is 18
so , age of stephanie is x-5 = 18-5 = 13
stephanie is 13 years old.

3 0

3 years ago

Three consecutive integers sum to 6. What is the least of these integers?

dexar [7]

Answer:

The least of the three integers is 1.

Step-by-step explanation:

Hi there!

Let x be equal to the least of these integers.

Let x+1 and x+2 be the next consecutive integers.

We're given that these integers have a sum os 6.

We can use these to construct an equation:

$(x)+(x+1)+(x+2)=6$

Combine like terms:

$x+x+1+x+2=6\\x+x+x+1+2=6\\3x+3=6\\3x=3\\x=1$

Therefore, the least of these integers is 1.

The other two integers would be 2 and 3.

I hope this helps!

3 0

3 years ago