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Likurg_2 [28]
3 years ago
8

Select the three models that represent 35%.

Mathematics
1 answer:
My name is Ann [436]3 years ago
8 0
The top left corner, the bottom left corner, and the right bottom corner.
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Use the Green's Theorem to calculate the work done by the field [ F (x, y) = -3y^5 i + 5y^2x^3 j ] to move a particle along the
lianna [129]
\displaystyle\int_C\mathbf F\cdot\mathrm d\mathbf r=\iint_R\left(\frac{\partial(5y^2x^3)}{\partial x}-\frac{\partial(-3y^5)}{\partial y}\right)\,\mathrm dx\,\mathrm dy

\dfrac{\partial(5y^2x^3)}{\partial x}=15y^2x^2
\dfrac{\partial(-3y^5)}{\partial y}=-15y^2

=\displaystyle\int_{x=-2}^{x=2}\int_{y=-\sqrt{4-x^2}}^{y=\sqrt{4-x^2}}15y^2(x^2+1)\,\mathrm dy\,\mathrm dx

Converting to polar coordinates, the integral is equivalent to

=\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=2}15r^3\sin^2\theta(r^2\cos^2\theta+1)\,\mathrm dr\,\mathrm d\theta
=\displaystyle15\int_0^{2\pi}\int_0^2\left(\frac{r^5}4\sin^22\theta+r^3\sin^2\theta\right)\,\mathrm dr\,\mathrm d\theta
=\displaystyle\frac{15}4\left(\int_0^2r^5\,\mathrm dr\right)\left(\int_0^{2\pi}\sin^22\theta\,\mathrm d\theta\right)+15\left(\int_0^2r^3\,\mathrm dr\right)\left(\int_0^{2\pi}\sin^2\theta\,\mathrm d\theta\right)
=100\pi
6 0
3 years ago
How determine if it is proportional
siniylev [52]
If you cross multiply and the answers are the same.
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3 0
3 years ago
Which graph below shows plots of equivalent ratios for this situation?
Margaret [11]

Answer:

2

Step-by-step explanation:

5 0
3 years ago
3/8-1/4=?<br><br> Answer ……..
Vlad1618 [11]

Step 1: Find the LCD (Least Common Denominator)

The LCD between 4 and 8 is 8. Therefore, if I change all of the fractions to have a denominator of 8, the problem is as such:

3/8 - 2/8 = ?

Step 2: Subtract

3/8 - 2/8 = 1/8

Hope this helps!

5 0
3 years ago
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