Answer:
C
Step-by-step explanation:
We can solve simultaneous equations using substitution method, elimination method or graphical method. But for this purpose, we will be using the elimination method.
3x+4y=8 Equation 1
2x+y=42 Equation 2
Multiply Equation 1 by 2 and equation 2 by 3, so as to get the same coefficient for x
2(3x+4y=8)= 6x+8y=16 Equation 3
3(2x+y=42)= 6x+3y=126 Equation 4
Subtract equation 4 from 3, to eliminate x
6x-6x=0
8y-3y= 5y
16-126= -110
We now have 5y=-110
Divide both sides by 5,
y= -110/5
= -22
Substituting for y in equation 2
2x+(-22)= 42
2x= 42+22
2x=64
x= 64/2
= 32
(x, y)
(32, -22)
Answer:
5.2
Step-by-step explanation:
a^2+b^2=c^2
Where c is the length of hypotenuse
and a, b are lengths of the legs.
Put in 6 for c,
Put in 3 for a and you get 9+b^2=36
Subtract 9 from both sides and get b^2= 27
Then find the square root of both sides to get b, so the answer is the square root of 27.
The cloest square root is 5, then apporixmate the tenths value and see if they work.
Answer: 5.2
A. -9.2x + 9.3
1. Distribute -0.6 and -3 to the brackets (by multiplying )
2. Put together the "like terms"
3. Add all together
C because K is 1,-8 so if you go up 1, -7, and right 4,5. So you get k(5,-7)
a. Dilation of 2nd equation by a factor of 12
b. The systems have the same solution, as dilations do not affect overall coordinates, changing side lengths but not angles
