Answer:
The answer <em>should </em>be:

The closest answer is A, so I'll go with that.
Step-by-step explanation:
So we have the rational expression:

First, remove the division sign. To do so, turn the division into multiplication and flip the second term:

Now, simplify. From the first term, in the numerator, factor out a x. On the second term, factor out a 2x in the numerator and a x in the denominator:

Multiply straight across:

Cancel out the (2x-7):

Cancel out the x:

At this point, we can factor the (4x^2-9) term, but we won't be able to cancel it out. Thus, this is the simplest it can get.
To get the answer, expand the numerator:

Thus, the answer is...
A?