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photoshop1234 [79]
3 years ago
12

What is negative 8 over 12?

Mathematics
2 answers:
Sedaia [141]3 years ago
7 0
That would be \frac{-8}{12}, but it is also equal to just -\frac{8}{12}. You would simplify the \frac{8}{12} part, and you would get \frac{2}{3}, or if you need a decimal, 0.6666...
But don't forget the negative part, so the answer would be -\frac{2}{3} or -0.6666...
Lesechka [4]3 years ago
4 0
<span>After simplify it, it equal to -2/3,it also equal to -0.666...</span>
You might be interested in
Let X denote the amount of time a book on two-hour reserve is actually checked out, and suppose the cdf is the following. F(x) =
Troyanec [42]

Answer:

a) P (x <= 3 ) = 0.36

b) P ( 2.5 <= x <= 3  ) = 0.11

c) P (x > 3.5 ) = 1 - 0.49 = 0.51

d) x = 3.5355

e) f(x) = x / 12.5

f) E(X) = 3.3333

g) Var (X) = 13.8891  , s.d (X) = 3.7268

h) E[h(X)] = 2500

Step-by-step explanation:

Given:

The cdf is as follows:

                           F(x) = 0                  x < 0

                           F(x) = (x^2 / 25)     0 < x < 5

                           F(x) = 1                   x > 5

Find:

(a) Calculate P(X ≤ 3).

(b) Calculate P(2.5 ≤ X ≤ 3).

(c) Calculate P(X > 3.5).

(d) What is the median checkout duration ? [solve 0.5 = F()].

(e) Obtain the density function f(x). f(x) = F '(x) =

(f) Calculate E(X).

(g) Calculate V(X) and σx. V(X) = σx =

(h) If the borrower is charged an amount h(X) = X2 when checkout duration is X, compute the expected charge E[h(X)].

Solution:

a) Evaluate the cdf given with the limits 0 < x < 3.

So, P (x <= 3 ) = (x^2 / 25) | 0 to 3

     P (x <= 3 ) = (3^2 / 25)  - 0

     P (x <= 3 ) = 0.36

b) Evaluate the cdf given with the limits 2.5 < x < 3.

So, P ( 2.5 <= x <= 3 ) = (x^2 / 25) | 2.5 to 3

     P ( 2.5 <= x <= 3  ) = (3^2 / 25)  - (2.5^2 / 25)

     P ( 2.5 <= x <= 3  ) = 0.36 - 0.25 = 0.11

c) Evaluate the cdf given with the limits x > 3.5

So, P (x > 3.5 ) = 1 - P (x <= 3.5 )

     P (x > 3.5 ) = 1 - (3.5^2 / 25)  - 0

     P (x > 3.5 ) = 1 - 0.49 = 0.51

d) The median checkout for the duration that is 50% of the probability:

So, P( x < a ) = 0.5

      (x^2 / 25) = 0.5

       x^2 = 12.5

      x = 3.5355

e) The probability density function can be evaluated by taking the derivative of the cdf as follows:

       pdf f(x) = d(F(x)) / dx = x / 12.5

f) The expected value of X can be evaluated by the following formula from limits - ∞ to +∞:

         E(X) = integral ( x . f(x)).dx          limits: - ∞ to +∞

         E(X) = integral ( x^2 / 12.5)    

         E(X) = x^3 / 37.5                    limits: 0 to 5

         E(X) = 5^3 / 37.5 = 3.3333

g) The variance of X can be evaluated by the following formula from limits - ∞ to +∞:

         Var(X) = integral ( x^2 . f(x)).dx - (E(X))^2          limits: - ∞ to +∞

         Var(X) = integral ( x^3 / 12.5).dx - (E(X))^2    

         Var(X) = x^4 / 50 | - (3.3333)^2                         limits: 0 to 5

         Var(X) = 5^4 / 50 - (3.3333)^2 = 13.8891

         s.d(X) = sqrt (Var(X)) = sqrt (13.8891) = 3.7268

h) Find the expected charge E[h(X)] , where h(X) is given by:

          h(x) = (f(x))^2 = x^2 / 156.25

  The expected value of h(X) can be evaluated by the following formula from limits - ∞ to +∞:

         E(h(X))) = integral ( x . h(x) ).dx          limits: - ∞ to +∞

         E(h(X))) = integral ( x^3 / 156.25)    

         E(h(X))) = x^4 / 156.25                       limits: 0 to 25

         E(h(X))) = 25^4 / 156.25 = 2500

8 0
3 years ago
Food inspectors inspect samples of food products to see if they are safe. This can be thought of as a hypothesis test with the f
Novay_Z [31]

Answer:

Type II error

Step-by-step explanation:

According to the definition of type II error, the type II error arises when we wrongfully accept the null hypothesis. It means that when we accept our null hypothesis and null hypothesis is not correct then type II error arises. So according to situation we are accepting the null hypothesis that the food is safe but it is actually not safe. Hence the given situation represents type II error.

7 0
2 years ago
1E. The number 2A5A0A2 is divisible by 99. What is the digit A?
kirza4 [7]

Answer: A = 3

Step-by-step explanation:

The digit is 3. If A is 3, the number

2A5A0A2 becomes 2353032. We then divide by 99 and this will be:

= 2353032/99

= 23768

If we use 1, we'll have 2151012. Dividing by 99 gives:

= 2151012 / 99

= 21727.39

If we use 2, we'll have 2252022. Dividing by 99 gives:

= 2252022 / 99

= 22747.69

If we use 4, we will have 2454042. Dividing by 99 gives:

= 2454042 / 99

= 24788.30

If we use 5, we will have 2555052. Dividing by 99 gives:

= 2555052 / 99

= 25808.61

If we use 6, we will have 2656062. Dividing by 99 gives:

= 2656062 / 99

= 26828.91

If we use 7, we will have 2757072. Dividing by 99 gives:

= 2757072 / 99

= 27849.21

If we use 8, we will have 2858082. Dividing by 99 gives:

= 2858082 / 99

= 28869.52

If we use 9, we will have 2959092. Dividing by 99 gives:

= 2959092 / 99

= 29889.82

If we use 0, we will have 2050002. Dividing by 99 gives:

= 2050002 / 99

= 20707.09

Therefore, A is 3 as it gives 2353032 which divides 99 successfully without remainder.

5 0
2 years ago
Refer to the equation 2x − 3y = 18.
Mice21 [21]

There is the table. <3

7 0
3 years ago
John made this model to show \frac{4}{7}\times\frac{13}{9} 7 4 ​ × 9 13 ​ Using John's model, what is \frac{4}{7}\times\frac{13}
harkovskaia [24]

Answer:

\frac{4}{7}\times\frac{13}{9} = \frac{52}{63}

Step-by-step explanation:

Given

See attachment for model

Required

Determine \frac{4}{7}\times\frac{13}{9} from the model

The model is represented by:

\frac{4}{7}\times\frac{13}{9} = \frac{4}{7}\times\frac{9}{9} + \frac{4}{7}\times\frac{4}{9}

To get: \frac{4}{7}\times\frac{9}{9}, we consider the first partition

The number of shaded box is 63 ---- this represents the denominator

The total boxes shaded at the bottom is 36 ---- this represents the numerator

So, we have:

\frac{4}{7}\times\frac{9}{9} = \frac{36}{63}

To get: \frac{4}{7}\times\frac{9}{9}, we consider the first partition

The number of shaded box is 63 ---- this represents the denominator

The total boxes shaded at the bottom is 16 (do not count the gray boxes) ---- this represents the numerator

So, we have:

\frac{4}{7}\times\frac{4}{9} =\frac{16}{63}

The equation becomes:

\frac{4}{7}\times\frac{13}{9} = \frac{4}{7}\times\frac{9}{9} + \frac{4}{7}\times\frac{4}{9}

\frac{4}{7}\times\frac{13}{9} = \frac{36}{63} + \frac{16}{63}

\frac{4}{7}\times\frac{13}{9} = \frac{36+16}{63}

\frac{4}{7}\times\frac{13}{9} = \frac{52}{63}

5 0
2 years ago
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