First we calculate the z-score for this situation.
Finding <em>P</em>(x < 5.3) is the same as finding <em>P</em>(<em>z</em> < -0.8). Using a table of standard normal distribution and z-scores we see that the probability is 0.21186.
Answer:
Per hour decay of the isotope is 0.96%.
Step-by-step explanation:
Amount of radioactive element remaining after t hours is represented by
where a = initial amount
t = duration of decay (in hours)
Amount remaining after 1 hour will be,
y = 0.9904a
So amount of decay in one hour = a - 0.9904a
= 0.0096a gms
Percentage decay every hour = 
= 
= 0.958 %
≈ 0.96 %
Therefore, per hour decay of the radioactive isotope is 0.96%.
<span>3^5 * 6^-6 / 3^3 * 6^-4
= 3^2 6^-2
= 3^2 / 6^2
= 9/36
=1/4
answer
</span><span>C.
1/4</span>
Answer:
12.
Square root = 37,
Step-by-step explanation:
40^2 = 1600
35^2 = 30 * 40 + 25 = 1225
So the requred square is between 35 and 40
38^2 = 1444
37^2 = 1369 - so its this one.
Required difference = 1381 - 1369 = 12.
Hope this helps..................
