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Stels [109]
3 years ago
7

What will the range values be for the function f(g) = 3g - 5 for the domain {-1.5, 2, 4}?

Mathematics
1 answer:
DochEvi [55]3 years ago
5 0
3(-1.5)-5=
-4.5-5=
-9.5

3(2)-5=
6-5=
1

3(4)-5=
12-5=
7

{f(-1.5),f(2),f(4)} = {-9.5,1,7} 
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What is the value of the expression 7- x when x =2.
Schach [20]

Answer:

5 is the answer of the equation

6 0
2 years ago
Read 2 more answers
What numbers go in the sqaures?
givi [52]

On the first two pairs you need to write 3 and 4, and 6 and 2.

On the second page we have:

1) 4

2) 2 and 7

3) 1

4) 1 and 3

5) 3.

<h3>What numbers go in the squares?</h3>

a) Here we just need to use scientific notation.

For the first case, the numbers that go in the exponent boxes are the same ones that go in the example, which are 4 in the first one and 2 on the second one.

Then, if we want the difference to be 29,400, then we can use 3 on the first box and 6 on the second. OR, because this is an absolute value, we can just invert those.

This is:

6 and 2 on the first two squares, and 3 and 4 on the second two squares.

b) Here we want to make perfect squares.

For example, on the first case we have:

x*2*2

We need to find the value of x such that this is a perfect square. Notice that we can rewrite this as:

x*2*2 = x*4

Then it only is a perfect square if x = 4.

For the second case:

14*x*y

This is only a perfect square if x*y = 14

Then we can use x = 2 and y = 7.

With similar reasoning, on the next box we have:

2*8*x

2*8 = 16, is already a perfect square, so x = 1.

The next one is:

x*3*y

Here we can define x = 3 and y = 1, so we get a perfect square.

Finally:

3*x

Here the only possible value of x is 3.

If you want to learn more about perfect squares:

brainly.com/question/1538726

#SPJ1

5 0
2 years ago
The vertex of the parabola below is at the point (1, 3), and the point (2, 6) is on the parabola. What is the equation of the pa
lbvjy [14]

Easily we can use formula y=(x-h)^2 +k

as equation of a parabola if vertex was (h,k):

Y=(x-1)^2 + 3

and maybe node (2,6) is incorrect for this vertex of a parabola!!!

3 0
3 years ago
Please help! I’ll mark brainliest
OLga [1]
The answer would be 6
8 0
2 years ago
Given the graph, find the distance of GH. Round to the nearest tenth.
lord [1]

Answer:

GH = 6.3 units

Step-by-step explanation:

Assuming that 1 box represents 1 unit, the coordinate pair of G = (-2, -3), while H = (0, 3).

Distance between G and H = d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Let,

G(-2, -3) = (x_1, y_1)

H(0, 3) = (x_2, y_2)

GH = \sqrt{(0 - (-2))^2 + (3 - (-3))^2}

GH = \sqrt{(2)^2 + (6)^2}

GH = \sqrt{4 + 36} = \sqrt{40}

GH = 6.3 units (nearest tenth)

5 0
3 years ago
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