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2 years ago

What is the product of 38x$12

Mathematics

2 answers:

maria [59]2 years ago

7 0

The product of 38 x 12 would be 456 but since you're counting with money then it would be $456. :D

bulgar [2K]2 years ago

4 0

The product 38×$12 is $456

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A cellular phone company monitors monthly phone usage. The following data represent the monthly phone use in minutes of one part

Sergeu [11.5K]

Answer:

The standard deviation increased but there was no change in the interquantile range

Step-by-step explanation:

We are given the following data in the question:

320, 411, 348, 537, 420, 449, 462, 403, 454, 517, 515, 358, 438, 541, 387, 368, 502, 437, 431, 428.

n = 20

a) Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{8726}{20} = 436.3$

Sum of squares of differences =

13525.69 + 640.09 + 7796.89 + 10140.49 + 265.69 + 161.29 + 660.49 + 1108.89 + 313.29 + 6512.49 + 6193.69 + 6130.89 + 2.89 + 10962.09 + 2430.49 + 4664.89 + 4316.49 + 0.49 + 28.09 + 68.89 = 75924.2

$S.D = \sqrt{\frac{75924.2}{19}} = 63.21$

Sorted Data = 320, 348, 358, 368, 387, 403, 411, 420, 428, 431, 437, 438, 449, 454, 462, 502, 515, 517, 537, 541

$IQR = Q_3 - Q_1\\Q_3 = \text{upper median},\\Q_1 = \text{ lower median}$

$Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}$

$Median = \frac{431 + 437}{2} = 434$

$Q_1 = \frac{387 + 403}{2} = 395\\\\Q_3 = \frac{462 + 502}{2} = 482$

IQR = $482 - 395 = 87$

b) After changing the observation

0, 411, 348, 537, 420, 449, 462, 403, 454, 517, 515, 358, 438, 541, 387, 368, 502, 437, 431, 428

$Mean =\displaystyle\frac{8406}{20} = 420.3$

Sum of squares of differences =

176652.09 + 86.49 + 5227.29 + 13618.89 + 0.09 + 823.69 + 1738.89 + 299.29 + 1135.69 + 9350.89 + 8968.09 + 3881.29 + 313.29 + 14568.49 + 1108.89 + 2735.29 + 6674.89 + 278.89 + 114.49 + 59.29 = 247636.2

$S.D = \sqrt{\frac{247636.2}{19}} = 114.16$

Sorted Data = 0, 348, 358, 368, 387, 403, 411, 420, 428, 431, 437, 438, 449, 454, 462, 502, 515, 517, 537, 541

$Median = \frac{431 + 437}{2} = 434$

$Q_1 = \frac{387 + 403}{2} = 395\\\\Q_3 = \frac{462 + 502}{2} = 482$

IQR = $482 - 395 = 87$

Thus. the standard deviation increased but there was no change in the interquantile range.

5 0

2 years ago

(-11)-((-7)+5 help me solve please !!

nekit [7.7K]

Answer:

1 or -9, depends on the problem, see below.

Step-by-step explanation:

-11--7+5

Two negatives make a positive so our new equation is:

-11+7+5

-11+7 is -4, so:

-4+5

And this leaves us with:

But I saw there was a parentheses, was it misplaced or was one not added? If one was not ended to the end, then the answer would be different.

(-11)-((-7)+5)

-7+5 is negative 2, so:

-11-(-2)

Once again, two negatives make a positive, so our new equation would be:

-11+2

Which gets us:

-9

6 0

2 years ago

A set of n = 10 pairs of scores has ΣX = 25, ΣY = 30, and ΣXY = 74. What is the value of SP for these data?

Aleksandr-060686 [28]

I think it's B

Not 100% sure but I think

3 0

2 years ago

Can someone help me with this pleaseeeeeee and no links :( :(

mart [117]

Answer:

a) 17 Weeks

b) $82

Step-by-step explanation:

a) 500-177=323

So, 323/19 = 17

So, he has been saving for 17 weeks.

b) 17+5=22

So, after 5 weeks he will get 5*19=95

So, 323+95=418

So, 500-418=82

Hence, he will need $82

Hope this helps you. :)

4 0

2 years ago

Write an equation or inequality to solve this problem. On three extra credit problems on a math test, students are given up to 4

vlada-n [284]

100-12 points=88
88 is the maximum raw score possible..

: 3

4 0

2 years ago

Read 2 more answers