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emmainna [20.7K]
3 years ago
12

Express 2log 4 + 3log 2 as a single logarithm

Mathematics
1 answer:
jeka943 years ago
3 0

Answer:

Step-by-step explanation:

WHEN ADDING TWO LOGS TO COMPRESS THEM YOU MULTIPLY THE TERMS

LOG(4^2)(2^3)

LOG(16)(8)

LOG(128)

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5(x+4)+16<br><br> Match each of the following with Equivalent Expression listed on the right
son4ous [18]
5(x+4)+16
5x+20+16
And then the solution is 5x+36
6 0
3 years ago
What scale factor was applied to the first rectangle to get the resulting image? The answer is a decimal. The big rectangle is 2
Juli2301 [7.4K]
Scale factor is always (new/original)

so it depends which rectangle came first. if it started as large and was dilated to the smaller one, then the ratio is (.5/2.5) which simplifies to 1/5 or 0.2.
3 0
3 years ago
Simplify (3 + 2i)(7 − 5i).
erma4kov [3.2K]
Rule needed: i^2 = -1
Standard form a + bi

(3 + 2i)(7 - 5i) FOIL
3 * 7 = 21
3 * - 5i = - 15i
2i * 7 = 14i
2i * -5i = - 10i^2 = - 10 * -1 = 10
Putting it all back together.
31 - i
8 0
3 years ago
Read 2 more answers
How many equivalence relations are there on the set 1, 2, 3]?
Alex787 [66]

Answer:

We need to find how many number of equivalence relations are on the set {1,2,3}

A relation is an equivalence relation if it is reflexive, transitive and symmetric.

equivalence relation R on {1,2,3}

1.For reflexive, it must contain (1,1),(2,2),(3,3)

2.For transitive, it must satisfy: if (x,y)∈R then (y,x)∈R

3. For symmetric, it must satisfy: if (x,y)∈R,(y,z)∈R then (x,z)∈R

Since (1,1),(2,2),(3,3) must be there is R, (1,2),(2,1),(2,3),(3,2),(1,3),(3,1). By symmetry,

we just need to count the number of ways in which we can use the pairs (1,2),(2,3),(1,3) to construct equivalence relations.

This is because if (1,2) is in the relation then (2,1) must be there in the relation.

the relation will be an equivalence relation if we use none of these pairs (1,2),(2,3),(1,3) . There is only one such relation: {(1,1),(2,2),(3,3)}

we can have three possible equivalence relations:

{(1,1),(2,2),(3,3),(1,2),(2,1)}

{(1,1),(2,2),(3,3),(1,3),(3,1)}

{(1,1),(2,2),(3,3),(2,3),(3,2)}

6 0
3 years ago
What is an equation of the line that passes through (-2,3) and is parallel to y=5x + 4.Give your answer in slope intercept form
9966 [12]

Answer:

y= 5x+13

Step-by-step explanation:

<u>Slope- intercept form</u>

y= mx +b, where m is the gradient and b is the y-intercept.

Parallel lines have the same gradient.

y= 5x +4

Gradient of given line= 5

Thus, gradient of line= 5

Subst. m=5 into the equation.

y= 5x +b

To find the value of b, substitute a coordinate

When x= -2, y=3,

3= 5(-2) +b

3= -10 +b

b= 3 +10 <em>(</em><em>+</em><em>1</em><em>0</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em><em>)</em>

b= 13

Thus, the equation of the line is y= 5x +13.

8 0
3 years ago
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