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3 years ago

HELP HELP PLEASE!! ITS MATH 6

Mathematics

2 answers:

Lynna [10]3 years ago

7 0

Answer: B

Step-by-step explanation:

Wewaii [24]3 years ago

4 0

Answer:

the answer for your question is B

Step-by-step explanation:

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What is the image of this figure after this sequence of dilations?

frutty [35]

Answer:

Gshafaufqyffqyfwuauwuwuwuwiwiqiqiyehsi

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2 years ago

2x+5 is greater than 50

katrin2010 [14]

2x+5=50
-5 -5
—————-
2x = 45
Divide by 2
45/2 = 22.5
I hope this makes sense

6 0

3 years ago

Read 2 more answers

Can the distributive property be used to rewrite 6(9 - 4) ?

alukav5142 [94]

Answer:

yes distribute . . .

Step-by-step explanation:

the 6 to the 9 and the 4

6(9) - 6(4)=30

5 0

3 years ago

Use Newton’s Method to find the solution to x^3+1=2x+3 use x_1=2 and find x_4 accurate to six decimal places. Hint use x^3-2x-2=

luda_lava [24]

Let $f(x) = x^3 - 2x - 2$ . Then differentiating, we get

$f'(x) = 3x^2 - 2$

We approximate $f(x)$ at $x_1=2$ with the tangent line,

$f(x) \approx f(x_1) + f'(x_1) (x - x_1) = 10x - 18$

The $x$ -intercept for this approximation will be our next approximation for the root,

$10x - 18 = 0 \implies x_2 = \dfrac95$

Repeat this process. Approximate $f(x)$ at $x_2 = \frac95$ .

$f(x) \approx f(x_2) + f'(x_2) (x-x_2) = \dfrac{193}{25}x - \dfrac{1708}{125}$

Then

$\dfrac{193}{25}x - \dfrac{1708}{125} = 0 \implies x_3 = \dfrac{1708}{965}$

Once more. Approximate $f(x)$ at $x_3$ .

$f(x) \approx f(x_3) + f'(x_3) (x - x_3) = \dfrac{6,889,342}{931,225}x - \dfrac{11,762,638,074}{898,632,125}$

Then

$\dfrac{6,889,342}{931,225}x - \dfrac{11,762,638,074}{898,632,125} = 0 \\\\ \implies x_4 = \dfrac{5,881,319,037}{3,324,107,515} \approx 1.769292663 \approx \boxed{1.769293}$

Compare this to the actual root of $f(x)$ , which is approximately <u>1.76929</u>2354, matching up to the first 5 digits after the decimal place.

4 0

2 years ago

Dolly used 10 pints of ice cream at her birthday party. Each person was served 2/5 pint of ice cream. How many people were serve

KonstantinChe [14]

25 people were served

5 0

2 years ago