What's 4.50+4.50+2.39+2.39+1.99? What's the answer minus 25?? pls halp meh '-'

Charlie T. Mole ate 16 insects. Anabel H. Mole ate 26

den301095 [7]

Answer:

10

Step-by-step explanation:

this is easy... subtraction

6 0

3 years ago

Find the longer leg of the triangle.

Paha777 [63]

Answer:

Choice A. 3.

Step-by-step explanation:

The triangle in question is a right triangle.

The length of the hypotenuse (the side opposite to the right angle) is given.
The measure of one of the acute angle is also given.

As a result, the length of both legs can be found directly using the sine function and the cosine function.

Let $\text{Opposite}$ denotes the length of the side opposite to the $30^{\circ}$ acute angle, and $\text{Adjacent}$ be the length of the side next to this $30^{\circ}$ acute angle.

$\displaystyle \begin{aligned}\text{Opposite} &= \text{Hypotenuse} \times \sin{30^{\circ}}\\ &=2\sqrt{3}\times \frac{1}{2} \\&= \sqrt{3}\end{aligned}$ .

Similarly,

$\displaystyle \begin{aligned}\text{Adjacent} &= \text{Hypotenuse} \times \cos{30^{\circ}}\\ &=2\sqrt{3}\times \frac{\sqrt{3}}{2} \\&= 3\end{aligned}$ .

The longer leg in this case is the one adjacent to the $30^{\circ}$ acute angle. The answer will be $3$ .

There's a shortcut to the answer. Notice that $\sin{30^{\circ}} < \cos{30^{\circ}}$ . The cosine of an acute angle is directly related to the adjacent leg. In other words, the leg adjacent to the $30^{\circ}$ angle will be the longer leg. There will be no need to find the length of the opposite leg.

Does this relationship $\sin{\theta} < \cos{\theta}$ holds for all acute angles? (That is, $0^{\circ} < \theta$ ?) It turns out that:

$\sin{\theta} < \cos{\theta}$ if $0^{\circ} < \theta$ ;
$\sin{\theta} > \cos{\theta}$ if $45^{\circ} < \theta$ ;
$\sin{\theta} = \cos{\theta}$ if $\theta = 45^{\circ}$ .

4 0

3 years ago

Read 2 more answers

You bought 50 shares of stock at $55 per share and sold them for $61 per share. The sale involves a broker’s commission of $0.30

malfutka [58]

Answer:

The profit made is;

b) $285)

Step-by-step explanation:

The given parameters are;

The number of shares bought, n = 50

The price each share is bought, CP = $55

The amount at which each share is sold, SP = $61

The amount the broker received per share, E = $0.30

Therefore, the amount of profit, 'P', is given as follows;

P = n × (SP - CP - E)

By substituting the values for the variables, we have;

P = 50 × (61 - 55 - 0.3) = 285

The amount made as profit, P = $285.00.

6 0

3 years ago

Write an exponential equation in the form y = ab* whose graph passes through points (2, 18) and (5, 60.75).

DochEvi [55]

Let $y=ab^x,$ as described in the problem statement. Plugging in $x=2$ and $x=5$ gives us the equations $18=ab^2$ and $60.75=ab^5.$ Since $a,b$ are nonzero, we divide the second equation by the first to get $\frac{27}{8}=b^3,$ which means that $b=\frac{3}{2},$ after taking the cube root. Plugging this value for $b$ into the first equation, we now have $18=a(3/2)^2=\frac{9a}{4}.$ Solving gives $a=8,$ and our desired exponential equation is $\boxed{y=8\left(\frac{3}{2}\right)^x}.$